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Svetlanka [38]
2 years ago
14

Noah bought a new car. It gets 21.7miles per gallon of gas on the highway. His gas tank is able to hold 14 gallons of gas. How m

any miles can Noah travel on the highway on one tank of gas?
Mathematics
2 answers:
Shtirlitz [24]2 years ago
5 0

Answer:

303.8

Step-by-step explanation:

All you do for this is 21.7 * 14

loris [4]2 years ago
3 0
Noah can travel 303.8 miles
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Caleb and Sergio stacked boxes on a shelf. Caleb lifted 14 boxes and Sergio lifted 12 boxes. The boxes that Sergio lifted each w
Andre45 [30]

Answer:

b

Step-by-step explanation:

4 0
3 years ago
At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t
grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c) The expected value of the temperature increase is 17.5°C.

Step-by-step explanation:

Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

P(X

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

P(20

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5

Thus, the expected value of the temperature increase is 17.5°C.

7 0
4 years ago
What are the solutions of -x^2+4x=x-4
Stolb23 [73]

Answer:

x = -1 and x = 4

Step-by-step explanation:

Step 1:  Get everything to one side of the equation so it's set equal to zero..

-x² + 4x = x - 4  becomes...

  -x² + 3x + 4 = 0        (subtract x and add 4 to both sides)

    x² - 3x - 4 = 0  (divide both sides by -1, we want the x² term to be positive)

   (x - 4)(x + 1) = 0          (factor)

      so

x - 4 = 0,    then x = 4

and

x + 1 = 0,   then x = -1  

8 0
4 years ago
A new car battery is sold with a two-year warranty whereby the owner gets the battery replaced free of cost if it breaks down du
Mariana [72]

Answer:

4.01% probability that the battery will break down during the warranty period

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 45, \sigma = 12

a. What is the probability that the battery will break down during the warranty period

Warranty of 2 years = 24 months. So this is the pvalue of Z when X = 24.

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 45}{12}

Z = -1.75

Z = -1.75 has a pvalue of 0.0401

4.01% probability that the battery will break down during the warranty period

7 0
3 years ago
If someone can help me out I’d be blessed :)
Irina-Kira [14]

Answer:

гм ні, бо тільки Бог благословляє людей

Step-by-step explanation:

3 0
3 years ago
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