Solve by graphing: y=3(x-2)^2-3

Giving brainless I need the answer ASAP

GarryVolchara [31]

Answer:

Is this in Pearson Easybridge?

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

How do we get to the vertex if this is the function: n(x)= |-1/3x + 1| =2 ??

vagabundo [1.1K]

Answer:

ANSWER IS BELOW

Step-by-step explanation:

Find the properties of the given parabola.

Tap for more steps...

Direction: Opens Up

Vertex:

(

0

,

0

)

(0,0)

Focus:

(

0

,

3

4

)

(0,34)

Axis of Symmetry:

x

=

0

x=0

Directrix:

y

=

−

3

4

y=-34

Select a few

x

values, and plug them into the equation to find the corresponding

y

values. The

x

values should be selected around the vertex.

Tap for more steps...

x

y

−

2

4

3

−

1

3

0

1

3

xy-243-1130011333

Graph the parabola using its properties and the selected points.

Direction: Opens Up

Vertex:

(

0

,

0

)

(0,0)

Focus:

(

0

,

3

4

)

(0,34)

Axis of Symmetry:

x

=

0

x=0

Directrix:

y

=

−

3

4

y=-34

x

y

−

2

4

3

−

1

3

0

1

3

xy-243-1130011333

3 0

2 years ago

Find the absolute minimum and absolute maximum values of f on the given interval. f(t) = 3 (*sqaure root sign*) t (20 − t), [0,

mafiozo [28]

9514 1404 393

Answer:

maximum: 15∛5 ≈ 25.6496392002
minimum: 0

Step-by-step explanation:

The minimum will be found at the ends of the interval, where f(t) = 0.

The maximum is found in the middle of the interval, where f'(t) = 0.

$f(t)=\sqrt[3]{t}(20-t)\\\\f'(t)=\dfrac{20-t}{3\sqrt[3]{t^2}}-\sqrt[3]{t}=\sqrt[3]{t}\left(\dfrac{4(5-t)}{3t}\right)$

This derivative is zero when the numerator is zero, at t=5. The function is a maximum at that point. The value there is ...

f(5) = (∛5)(20-5) = 15∛5

The absolute maximum on the interval is 15∛5 at t=5.

5 0

2 years ago

Mai will spend more than $23 on gifts. So far, she has spent $15. What are the possible additional amounts she will spend? Use c

mote1985 [20]

Answer:

c = ≥ (23 - 15) therefore c = ≥ 8

3 0

2 years ago

What is the area of a triangle whose side is 17 meters long

Lunna [17]

Answer:

125.141

Step-by-step explanation:

Assuming that this is an equilateral triangle, I am going to divide this triangle in half to get a right triangle.

17 is our hypotenuse

17/2 = 8.5, this is one of our legs

The other leg is our height, which we will find.

We use Pythagoras Theorem to find the height/leg: $a^{2} +b^{2} =c^{2}$

$17^{2} -8.5^{2} = 216.75$

$\sqrt{216.75}$ = 14.72243186

Now, we use another formula to find the area of the triangle: $\frac{Base*Height}{2}$

14.72243186 × 17 = 250.2813416

250.2813416 ÷ 2 = <u>125.1406708</u>

8 0

2 years ago