Answer:
(C) 18cm, 39cm, 21cm and 45cm.
Step-by-step explanation:
The quadrilateral HIJK has sides measuring 12 cm, 26 cm, 14 cm, and 30 cm.
When HIJK is dilated with a scale factor of 1.5, the side lengths becomes:
12 X 1.5 =18 cm
26 X 1.5 =39 cm
14 X 1.5 =21 cm
30 X 1.5 =45 cm
A dilation of HIJK with a scale factor of 1.5 will give us the side lengths:
18cm, 39cm, 21cm and 45cm.
<u>The correct option is C.</u>
Answer:
759.88 square inches
Step-by-step explanation:

V = x/t = 4.5 mil / 3 h = 1.5 mph
Since, v = 1.5 mph (or we can say that v is constant), distance and time vary directly and the constant of variation is 1.5 mph.
Answer:
w = 31
Step-by-step explanation:
To find the value of w:
We know that the three angles in a triangle add to 180 degrees
w + w + (4w-6) =180
Add like terms
6w-6 = 180
Add 6 to each side
6w -6+6 =180+6
6w = 186
Divide each side by 6
6w/6 = 186/6
w = 31
Answer:
7.3% of the bearings produced will not be acceptable
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.
So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.
Larger than 0.504
1 subtracted by the pvalue of Z when X = 0.504.



has a pvalue of 0.9938
1 - 0.9938= 0.0062
Smaller than 0.496
pvalue of Z when X = -1.5



has a pvalue of 0.0668
0.0668 + 0.0062 = 0.073
7.3% of the bearings produced will not be acceptable