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musickatia [10]
3 years ago
14

What is not equivalent to 65%

Mathematics
2 answers:
Nadya [2.5K]3 years ago
5 0

We need the answers?


finlep [7]3 years ago
3 0

anything other than 65/100 or 0.65

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Quadrilateral HIJK has sides measuring 12 cm, 26 cm, 14 cm, and 30 cm. Which could be the side lengths of a dilation of HIJK wit
matrenka [14]

Answer:

(C) 18cm, 39cm, 21cm and 45cm.

Step-by-step explanation:

The quadrilateral HIJK has sides measuring 12 cm, 26 cm, 14 cm, and 30 cm.

When HIJK is dilated with a scale factor of 1.5, the side lengths becomes:

12 X 1.5 =18 cm

26 X 1.5 =39 cm

14 X 1.5 =21 cm

30 X 1.5 =45 cm

A dilation of HIJK with a scale factor of 1.5 will give us the side lengths:

18cm, 39cm, 21cm and 45cm.

<u>The correct option is C.</u>

6 0
3 years ago
Please help me I’m so lost
Svetllana [295]

Answer:

759.88 square inches

Step-by-step explanation:

r =  \frac{1}{2}d =  \frac{1}{2} \times 44 = 22 \\    \\ area = \frac{1}{2}  \pi \:  {r}^{2}  \\ area =  \frac{1}{2}  \times 3.14 \times 22 \times 22 \\ area = 759.88 \: square \: inches

4 0
3 years ago
Read 2 more answers
Alan hikes 4.5 miles in 3 hours. Determine whether quantities (distance and time) vary directly or inversely and find the consta
Mrac [35]
V = x/t = 4.5 mil / 3 h = 1.5 mph
Since, v = 1.5 mph (or we can say that v is constant), distance and time vary directly and the constant of variation is 1.5 mph.
3 0
3 years ago
What is the value of X?
Leviafan [203]

Answer:

w = 31

Step-by-step explanation:

To find the value of w:

 We know that the three angles in a triangle add to 180 degrees

w + w + (4w-6) =180

Add like terms

6w-6 = 180

Add 6 to each side

6w -6+6 =180+6

6w = 186

Divide each side by 6

6w/6 = 186/6

w = 31

7 0
3 years ago
A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5
lara [203]

Answer:

7.3% of the bearings produced will not be acceptable

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 0.499, \sigma = 0.002

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.

So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.

Larger than 0.504

1 subtracted by the pvalue of Z when X = 0.504.

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.504 - 0.494}{0.002}

Z = 2.5

Z = 2.5 has a pvalue of 0.9938

1 - 0.9938= 0.0062

Smaller than 0.496

pvalue of Z when X = -1.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.496 - 0.494}{0.002}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.0668 + 0.0062 = 0.073

7.3% of the bearings produced will not be acceptable

4 0
4 years ago
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