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valina [46]
3 years ago
12

Multiply x^2-8x+15/3x * 8x/x-3

Mathematics
1 answer:
sergejj [24]3 years ago
5 0
You must follow the steps below:

 1. First, you should apply the dstributive property:

 =(x²-<span>8x+15/3x)(8x/x-3)
 =(8</span>x³-64x²+120x)/3x(x-3)

 2. As you can see, the common factor in the numerator is: "8x". So, you have:

 =8x(x²-8x+15)/3x(x-3)

 3. Then, when you simplify, you obtain:

 =8(x²-8x+15)/3(x-3)

 Therefore, the solution is: 8(x²-8x+15)/3(x-3)
 
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A total of 430 tickets were sold for the school play . They were either adult tickets or student tickets . There were 70 fewer s
Maurinko [17]
So first we assume that half is adult and have is student.

So
215 adult  215 student

Now since it said they were 70 less student tickets than adult tickets we subtract 70.
215 - 70 = 145

Now we add the 70 we subtracted from student tickets to the adult tickets.
215 + 70 = 285

So there were 
285 adult tickets sold and 145 student tickets sold

I hope this helped. Have a great day!
6 0
3 years ago
Solve x = 0.6x + 384
Gelneren [198K]
X = 0.6x + 384        |subtract 0.6x from both sides

0.4x = 384    |divide both sides by 0.4

x = 960
8 0
3 years ago
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Divide 240 in the ratio of 5:3
zubka84 [21]
The answer to your question  is 25:15
6 0
3 years ago
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A researcher compares differences in positivity between participants in a low-, middle-, or upper-middle-class family. If she ob
777dan777 [17]

Answer:

(2, 12)

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

If we assume that we have 3 groups and on each group from j=1,\dots,n_j we have n_j individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2  

SS_{between=Treatment}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2  

And we have this property  

SST=SS_{between}+SS_{within}  

The degrees of freedom for the numerator on this case is given by df_{num}=k-1=3-1=2 where k =3 represent the number of groups.  

The degrees of freedom for the denominator on this case is given by df_{den}=df_{between}=N-K=15-3=12.  

And the total degrees of freedom would be df=N-1=15 -1 =14  

And the correct answer would be 2 degrees of freedom for the numerator and 12 for the denominator

(2, 12)

3 0
3 years ago
What is 96 written in expanded form?
natita [175]

Answer:

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Step-by-step explanation:

90 + 6 = 96

<u>ALTERNATIVE</u><u>:</u>

96 - 6 = 90

6 0
3 years ago
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