Answer:
No, because there is no data for the interval.
Answer:
Step-by-step explanation:
All the interior angles are of measure 60 degrees.
We want to find the height of this triangle. Call it h. On the left side of this illustration is a right triangle with height h and base (1/2)(10), or 5.
The ratio of height to base is the tangent of 60 degrees:
h
tan 60 degrees = --------------
5
h
and tan 60 degrees = 1.73 = ------
5
Multiplying both sides of this equation by 5 yields h = 8.66. This is |BD|. This is the same as Answer B.
The answer is a.0.32 km.
The speed that a tsunami can travel is modeled by the equation is s = 356√d.
It is given:
s = 200 km/h
d = ?
Now, let's substitute s in the equation and find d:
s = 356√d
200 = 356√d
√d = 200 ÷ 356
√d = 0.562
Now, let's square both sides of the equation:
(√d)² = (0.562)²
d = (0.562)² = 0.316 ≈ 0.32
Therefore, <span> the approximate depth (d) of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.</span>
Answer: The graph is attached.
Step-by-step explanation: The given functions whose graphs are to be compared are as follows:
In the attached figure, the graphs of both (A) and (B) are shown. We can easily see see from there, the shapes of both the graphs are same.
But, at x = 0, y = ∞ and at x = ∞, y = 0 in graph (A).
At x = 0, y = ∞ and at x = ∞, y = 6 in graph (B).
Thus, the comparison can be seen in the figure very clearly.
