1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
marissa [1.9K]
3 years ago
14

Element X is a radioactive isotope such that every 82 years, its mass decreases by half. Given that the initial mass of a sample

of Element X is 8900 grams, how long would it be until the mass of the sample reached 7700 grams, to the nearest tenth of a year
Chemistry
1 answer:
lesantik [10]3 years ago
4 0

Answer: 17 years

Explanation:

Expression for rate law for first order kinetics  for radioactive substance is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

a) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.693}{82years}=8.4\times 10^{-3}years^{-1}

b) for 8900 g of the mass of the sample to reach  7700 grams

t=\frac{2.303}{8.4\times 10^{-3}}\log\frac{8900}{7700}

t=17years

Thus it will take 17 years

You might be interested in
A sample that weighs 107.75 g is a mixture of 30% helium atoms and 70% krypton atoms. How many particles are present in the samp
My name is Ann [436]
30% of 107.75 g is 32.325g so there are about 8.08125 mol of He which is
4.86 x 10^24 particles
70% of 107.75 g is 75.425g so there are about .9 mol of Kr which is 
5.42 x 10^23 paticles
In the whole sample, there are about 5.41 x 10^24 particles

7 0
4 years ago
The law of conservation of mass states that mass must be created or destroyed in ordinary chemical and physical changes. Is this
Anuta_ua [19.1K]

Answer:

The statement stated above is true.

6 0
3 years ago
If you performed a combustion reaction of 2-ethyl, 4-methylpropene, what products would you expect to be present?
Dafna1 [17]

The question is incomplete, here is the complete question:

If you performed a combustion reaction of 2-ethyl-1-methylpropene, what products would you expect to be present?

Answer: The products of the combustion of 2-ethyl-1-methylpropene are carbon dioxide and water.

<u>Explanation:</u>

Combustion reaction is defined as the reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.

\text{Hydrocarbon}+O_2\rightarrow CO_2+H_2O

We are given a chemical compound, which is 2-ethyl-1-methylpropene. The chemical formula of this compound is C_6H_{13}

The chemical equation for the combustion of 2-ethyl-1-methylpropene follows:

4C_6H_{13}+37O_2\rightarrow 24CO_2+26H_2O

By Stoichiometry of the reaction:

4 moles of 2-ethyl-1-methylpropene reacts with 37 moles of oxygen gas to produce 24 moles of carbon dioxide and 26 moles of water

Hence, the products of the combustion of 2-ethyl-1-methylpropene are carbon dioxide and water.

6 0
4 years ago
As you read from left to right across the periodic table atomic numbers and what by one of each element
Illusion [34]

Answer:

As we read from left to right across the periodic table atomic numbers are increased by one each of element.

Explanation:

As we move from left to right across the periodic table the atomic number is increased by one and the number of valance electron in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.

8 0
4 years ago
I need help with this…and can you so the work if you can!!
zzz [600]

Answer:

88 grams CO2

Explanation:

Convert from grams to moles to mole ratio to grams again

32 g CH4 * 1 mol CH4/16 g CH4 * 1 mol CO2/1 mol CH4 * 44 grams CO2 = 88 grams CO2

Lemme know if u need more explanation!

4 0
3 years ago
Other questions:
  • Which is a conversion factor for this statement of equality: 12 in. = 1 foot?
    6·2 answers
  • The solubility of copper(i) chloride is 3.91 mg per 100.0 ml of solution. calculate ksp for cucl (cucl=99.00 g mol-1).
    10·2 answers
  • How do the periods of rotation and revolution for the gas giant planets differ from those on earth?
    9·1 answer
  • The nucleus of the atom was discovered by what pioneering experiment?
    6·2 answers
  • What role do valence electrons play in the formation of compounds from elements?
    6·1 answer
  • PH CHEM, PLEASE HELP QUICK! NO LINKS/VIRUSES PLEASE!
    13·1 answer
  • (science) <br> hurry help!!<br><br> All commonly abused drugs are illegal.<br><br> true or false
    8·2 answers
  • Ammonium perchlorate is the solid rocket fuel used by the U.S. Space Shuttle. It reacts with itself to produce nitrogen gas , ch
    6·1 answer
  • How are elements in the same family in the periodic table alike?
    5·2 answers
  • Hot filtration is a technique in which the mixture is heated and all the glassware is also heated for the filtration. When shoul
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!