Answer:
D. 91.0%
Explanation:
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In this case, for the given chemical reaction:
Next, since silver nitrate (molar mass 169.87 g/mol) is in a 2:1 molar ratio with silver sulfide (molar mass 247.8 g/mol), we compute its theoretical yield as shown below:
Next, we compute the percent yield as:
Hence, answer is D. 91.0%.
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