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Stolb23 [73]
3 years ago
7

What volume would a 0.871 gram sample of air occupy if the density of air is 1.29 g/L?

Chemistry
2 answers:
-Dominant- [34]3 years ago
7 0

Answer:

\boxed{\text{675 mL}}

Explanation:

V = \text{0.871 g} \times \dfrac{\text{1 L}}{\text{1.29 g}} = \text{0.675 L} = \textbf{675 mL}\\\\\text{The volume of air is } \boxed{\textbf{675 mL}}

IgorLugansk [536]3 years ago
3 0

Answer : The volume of the sample of air will be 0.675 L

Explanation :

Density : It is defined as the mass of a substance contained per unit volume.

Formula used :

Density=\frac{Mass}{Volume}

Given:

Mass of sample of air = 0.871 g

Density of air = 1.29 g/L

By using formula, we get:

1.29g/L=\frac{0.871g}{Volume}

Volume=0.675L

Thus, the volume of the sample of air will be 0.675 L

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Dolomite is a mixed carbonate of calcium and magnesium. Calcium and magnesium carbonates both decompose upon heating to produce
Setler79 [48]

Answer:

72.03 %

Explanation:

Total mass of dolomite = 9.66 g

Let the mass of Magnesium carbonate = x g

The mass of calcium carbonate = 9.66 - x g

Calculation of the moles of Magnesium carbonate as:-

Molar mass of Magnesium carbonate = 122.44 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{x\ g}{84.3139\ g/mol}=\frac{x}{84.3139}\ mol

Calculation of the moles of calcium carbonate as:-

Molar mass of calcium carbonate = 100.0869 g/mol

Thus,

Moles= \frac{9.66 - x\ g}{100.0869\ g/mol}=\frac{9.66 - x}{100.0869}\ mol

According to the reaction shown below:-

MgCO_3\rightarrow MgO+CO_2

CaCO_3\rightarrow CaO+CO_2

In both the cases, the oxides formed from the carbonates in the 1:1 ratio.

So, Moles of MgO = \frac{x}{84.3139}\ mol

Molar mass of MgO = 40.3044 g/mol

Thus, Mass = Moles*Molar mass = \frac{x}{84.3139}\times 40.3044 \ g

Moles of CaO = \frac{9.66 - x}{100.0869}\ mol

Molar mass of CaO = 56.0774 g/mol

Thus, Mass = Moles*Molar mass = \frac{9.66 - x}{100.0869}\times 56.0774 \ g

Given that total mass of the oxide = 4.84 g

Thus,

\frac{x}{84.3139}\times 40.3044 +\frac{9.66 - x}{100.0869}\times 56.0774=4.84

\frac{40.3044x}{84.3139}+56.0774\times \frac{-x+9.66}{100.0869}=4.84

-694.1618435x+45673.48749\dots =40843.38968\dots

x=\frac{4830.09780\dots }{694.1618435}

x=6.9582

Thus, the mass of Magnesium carbonate = 6.9582 g

\%\ mass=\frac{Mass_{MgCO_3}}{Total\ mass}\times 100

\%\ mass=\frac{6.9582}{9.66}\times 100=72.03\ \%

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3 years ago
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Gas is heated from 480. K to 750. K and the pressure is kept constant, what final volume would result if the original volume was
attashe74 [19]
Charles law gives the relationship between volume and temperature of gas.
It states that at constant pressure volume is directly proportional to temperature
Therefore
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8 0
3 years ago
For a different reaction, the plot of the reciprocal of concentration versus time in seconds was linear with a slope of 0.056 M-
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Answer:

C_t=0.165M

Explanation:

From the question we are told that:

Slope K=0.056 M-1 s -1

initial Concentration C_1=2.2M

Time t=100

Generally the equation for Raw law is mathematically given by

\frac{1}{C}_t=kt+\frac{1}{C}_0

\frac{1}{C}_t=0.056*100+\frac{1}{2.2}_0

C_t=0.165M

4 0
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