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3 years ago

What volume would a 0.871 gram sample of air occupy if the density of air is 1.29 g/L?

Chemistry

2 answers:

-Dominant- [34]3 years ago

7 0

Answer:

$\boxed{\text{675 mL}}$

Explanation:

$V = \text{0.871 g} \times \dfrac{\text{1 L}}{\text{1.29 g}} = \text{0.675 L} = \textbf{675 mL}\\\\\text{The volume of air is } \boxed{\textbf{675 mL}}$

IgorLugansk [536]3 years ago

3 0

Answer : The volume of the sample of air will be 0.675 L

Explanation :

Density : It is defined as the mass of a substance contained per unit volume.

Formula used :

$Density=\frac{Mass}{Volume}$

Given:

Mass of sample of air = 0.871 g

Density of air = 1.29 g/L

By using formula, we get:

$1.29g/L=\frac{0.871g}{Volume}$

$Volume=0.675L$

Thus, the volume of the sample of air will be 0.675 L

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In a hospital laboratory, a 10.0 mL sample of gastric juice (predominantly HCl), obtained several hours after a meal, was titrat

LiRa [457]

Answer: 1.14

Explanation:

$HCl+NaOH\rightarrow NaCl+H_2O$

To calculate the molarity of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?\\V_1=10.0mL\\n_2=1\\M_2=0.1M\\V_2=7.2mL$

Putting values in above equation, we get:

$1\times M_1\times 10.0=1\times 0.1\times 7.2\\\\M_1=0.072M$

To calculate pH of gastric juice:

molarity of $H^+$ = 0.072

$pH=-log[H^+]$

$pH=-log(0.072)=1.14$

Thus the pH of the gastric juice is 1.14

3 0

3 years ago

Codons.

andrey2020 [161]

Answer:

1. C- Three.

2. A- Methionine

3. D- Translocation.

4. C- OH.

5. A - 5'

6. A - 3' carbon

7. A. adenine and guanine

Explanation:

1. A codon is a group of three nucleotide sequence that encodes or specifies an amino acid. This means that, during translation (second stage of gene expression), when a CODON is read, an amino acid is added to the growing peptide chain.

2. The codon that initiates the translation process is called a start codon. It has a sequence: AUG and it specifies Methionine amino acid. Hence, during translation where a tRNA binds to the mRNA codon to read it and add its corresponding amino acid, a tRNA with a complementary sequence of AUG (start codon) binds to it and carries Methionine amino acid.

3. Translocation is a process during translation whereby the mRNA-tRNA moeity moves forward in the ribosome to allow another codon to move into the vacant site for translation process to continue.

4. The sugar component of a nucelotide that makes up the nucleic acid (DNA or RNA) i.e. ribose or deoxyribose, contains an hydroxyll functional group (-OH).

5. A nucleotide consists of a pentose (five carbon) sugar, phosphate group and a nitrogenous base. The phosphate group (PO43-) is attached to the 5' carbon of the sugar molecule.

6. The free hydroxyll group (-OH) of the five carbon sugar molecule in DNA is attached to its 3' carbon.

7. Nitrogenous bases are the third component of a nucleotide, the other two being pentose sugar and phosphate group. The nitrogenous bases are four viz: Adenine, Guanine, Cytosine, and Thymine. These bases are classified into Purines and Pyrimidines based on the similarity in their structure. Adenine (A) and Guanine (G) are Purines because they possess have two carbon-nitrogen rings, as opposed to one possessed by Pyrimidines (Thymine and Cytosine).

7 0

3 years ago

The atom shown below is?

Volgvan

Answer:

Explanation:

Not likely to form any bonds because in it's last she'll it has 8 electrons and is therefore stable

8 0

2 years ago

What does amoeba use to move and ingest prey?

melomori [17]

The cytoplasm slides and forms a pseudopodium in front to move the cell forwards.