Question

What volume would a 0.871 gram sample of air occupy if the density of air is 1.29 g/L?

Answer 1

Answer:

$\boxed{\text{675 mL}}$

Explanation:

$V = \text{0.871 g} \times \dfrac{\text{1 L}}{\text{1.29 g}} = \text{0.675 L} = \textbf{675 mL}\\\\\text{The volume of air is } \boxed{\textbf{675 mL}}$

Answer 2

Answer : The volume of the sample of air will be 0.675 L

Explanation :

Density : It is defined as the mass of a substance contained per unit volume.

Formula used :

$Density=\frac{Mass}{Volume}$

Given:

Mass of sample of air = 0.871 g

Density of air = 1.29 g/L

By using formula, we get:

$1.29g/L=\frac{0.871g}{Volume}$

$Volume=0.675L$

Thus, the volume of the sample of air will be 0.675 L