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elena-14-01-66 [18.8K]
3 years ago
10

The amount of time it takes Heather to cook dinner is directly proportional to the number of ingredients involved. If it takes h

er t minutes to cook dinner when there are n ingredients involved how long does it take her to cook dinner when there are 15 ingredients involved?
Mathematics
2 answers:
Lemur [1.5K]3 years ago
6 0
15 minutes!

Since the ratio is 1 : 1, for every one ingredient it will take her one minute. 15 ingredients = 15 minutes.

Hope that helped!

:D®

P.S. I wonder what she's cooking.
Vlada [557]3 years ago
4 0

Answer:

\frac{15t}{n}\text{ minutes}

Step-by-step explanation:

Given,

Time taken to cook dinner with n ingredients = t minutes.

i.e. n ingredients = t minutes,

⇒ 1 ingredient = \frac{t}{n} minutes,

⇒ 15 ingredients = \frac{15t}{n} minutes,

Hence, it will take \frac{15t}{n} minutes to cook dinner when there are 15 ingredients involved.

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3 years ago
Find the number of the different ways, for 3 students to sit on 7 seats in one row.
qwelly [4]

Answer:

210

Step-by-step explanation:

Here comes the problem from Combination.

We are being asked to find the number of ways out in which 3 students may sit on 7 seats in a row. Please see that in this case the even can not be repeated.

Let us start with the student one. For him all the 7 seats are available to sit. Hence number of ways for him to sit = 7

Let us see the student second. For him there are only 6 seats available to sit as one seat has already been occupied. Hence number of ways for him to sit = 6

Let us see the student third. For him there are only 5 seats available to sit as two seat has already been occupied. Hence number of ways for him to sit = 5

Hence the total number of ways for three students to be seated will be

7 x 6 x 5

=210

3 0
4 years ago
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If x does not equal 16 then 2x+10 does not equal 42​
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3 years ago
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(1 point) A random sample of 600 movie goers in Flagstaff found 252 movie goers who had bought popcorn on their last visit. Find
garik1379 [7]

<u>Answer-</u>

A 95% confidence interval for the true percent of movie goers is 36.41% to 44.25%

<u>Solution-</u>

Given,

n = 600 (sample size)

x = 252 (number of people who bought)

Confidence interval = 95%, so z = 1.96

We know that,

\mu = M\pm Z(SE)

where,

M = sample mean

Z  = Z statistic determined by confidence level

SE = standard error of mean

Calculating the values,

M=\frac{x}{n} =\frac{242}{600} =0.4033

Z=1.96 from the tables

SE=\sqrt{\frac{M\times (1-M)}{n}}

\Rightarrow SE=\sqrt{\frac{0.4033\times (1-0.4033)}{600}}=0.02

Putting all the values in the formula,

\mu = M\pm Z(SE)

\mu = 0.4033\pm 1.96(0.02)

=0.4033\pm 0.0392

=0.4425, 0.3641

= 44.25\%,36.41\%

5 0
4 years ago
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