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2 years ago

(100 POINTS) Instructions:

Mathematics

1 answer:

erma4kov [3.2K]2 years ago

4 0

Answer:

Length: 15

Width: 12

Height: 13

Step-by-step explanation:

Hope this helps!

(Mark as brainleist plz)

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angle K and angle L are complementary angels. If the measurement of angle K =(3x+3) and the measurement of angle L =(10x-4).what

spayn [35]

The measurement of two angles is 24° and 66°

Step-by-step explanation:

First of all, let us define complementary angles

The angles whose sum is 90° are called complementary angles

Given

∠K = (3x+3)

∠L = (10x-4)

According to the definition,

$K+L = 90\\3x+3 + 10x-4 = 90\\13x -1 = 90\\13x-1+1 = 90+1\\13x = 91$

Dividing both sides by 13

$\frac{13x}{13} = \frac{91}{13}\\x = 7$

So,

∠K = 3x + 3 = 3(7) + 3 = 21+3 = 24°

∠L = 10x - 4 = 10(7) -4 =70 -4 = 66°

Hence,

The measurement of two angles is 24° and 66°

Keywords: Complementary angles, Angles

Learn more about complementary angles at:

#LearnwithBrainly

3 0

3 years ago

Mandarinka [93]

Answer:

2.69 maybe not so sure ..

8 0

3 years ago

Which is equal to -214°?

Neporo4naja [7]

Answer: -107pi/45 radians

5 0

2 years ago

A piece of rope 27m long is cut into two pieces so that one piece is four-fifths as long as the other. Find the length of each p

nata0808 [166]

Answer:

x+.8x=27

1.8x=27

x=15

4/5(15)=12

So 15 and 12

Step-by-step explanation:

8 0

2 years ago

Match each expression in the left column with the correct product in the right column.

lesya692 [45]

Answer:

-6

-6i

Step-by-step explanation:

1) √4 . √-3 . √-3

$\sqrt{4} = 2$

$\sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2$

$\sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 =$ -6

2) √-4 . √-3 . √-3

$\sqrt{-4} = 2i$ .

Therefore, $\sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1} \times -3 = 2i \times (-3) =$ - 6i

3) √4 . √3 . √-3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1}$

$\implies 2 \times 3i =$ 6i

4) √4 . √3 . √3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{3} = (\sqrt{3})^2 = 3$

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0

3 years ago