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3 years ago

Which equation demonstrates the distributive property?

Mathematics

2 answers:

xxMikexx [17]3 years ago

8 0

Your answer is going to be : B AND PLEASE MARK ME AS BRAINLIEST CAUSE I'VE NEVER GOT BRAINLIEST BEFORE(LIKE EVER)

Makovka662 [10]3 years ago

5 0

The distributive property is demonstrated by B.
A demonstrate the commutative property of addition, C demonstrates the associative property of multiplication, and D demonstrates both the commutative and the associative properties of multiplication.

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if two circles have circumference of 12 pi inches and 18 pi inches,find the ratio between their radii

djverab [1.8K]

The formula for the circumference is:
$2\pi r$
So to find first radius:
$2\pi r = 12\pi \\ \\ \pi r = 6\pi \\ \\ r = 6$
Second radius:
$2\pi r = 18\pi \\ \\ \pi r = 9\pi \\ \\ r = 9$
The ratio between them is:
$\frac{6}{9} = \frac{2}{3} = 0.66667$

8 0

3 years ago

Two dice are rolled; the numbers add to 11.

Roman55 [17]

Answer:

5+6

7+4

8+3

9+2

10+1

11+0

Step-by-step explanation:

there are infinite possibiltiys

ex:

10.000000001+0.000000009

3 0

2 years ago

Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both, in case

lozanna [386]

Answer:

0.3339 = 33.39% probability that both Dave and Mike will show up

Step-by-step explanation:

Probability of independent events:

If A and B are independent events, the probability of both happening at the same time is given by:

$P(A \cap B) = P(A)P(B)$

In this question:

Event A: Dave shows up.

Event B: Mike shows up.

Christine knows that there is a 47% chance that Dave will not show up and a 37% chance that Mike will not show up.

This means that $P(A) = 1 - 0.47 = 0.53, P(B) = 1 - 0.37 = 0.63$ .

a. What is the probability that both Dave and Mike will show up

$P(A \cap B) = P(A)P(B) = 0.53*0.63 = 0.3339$

0.3339 = 33.39% probability that both Dave and Mike will show up

8 0

2 years ago

AABC has vertices at A(1, -9), B(8,0), and C(9,-8).

Rainbow [258]

Check the picture below.

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{-9})\qquad B(\stackrel{x_2}{8}~,~\stackrel{y_2}{0}) ~\hfill AB=\sqrt{[ 8- 1]^2 + [ 0- (-9)]^2} \\\\\\ AB=\sqrt{7^2+(0+9)^2}\implies AB=\sqrt{7^2+9^2}\implies \boxed{AB=\sqrt{130}} \\\\[-0.35em] ~\dotfill$

$B(\stackrel{x_1}{8}~,~\stackrel{y_1}{0})\qquad C(\stackrel{x_2}{9}~,~\stackrel{y_2}{-8}) ~\hfill BC=\sqrt{[ 9- 8]^2 + [ -8- 0]^2} \\\\\\ BC=\sqrt{1^2+(-8)^2}\implies \boxed{BC=\sqrt{65}}$

now, we could check for the CA distance, however, we already know that AB ≠ BC, so there's no need.

6 0

2 years ago

The sequence an = 8, 13, 18, 23, ... is the same as the sequence a1 = 8, an = an-1 + 5.

harkovskaia [24]

Actually, this answer would be true. Why?

The first equation is: a(sub n) = 8, 13, 18, 23

The second is: a(sub 1)=8 ; a(sub n)= a(sub n-1)+5
if you wish to find the second term, plug two into the equation for n
8+5=13
to find the third, plug the second term, 13, in for n.
13+5=18.

Hope this helped! I know it's a bit on the late side, but at least you can get the general idea!

8 0

3 years ago

Read 2 more answers