Isabella is comparing the values below. Which list shows the values in descending order? 7.42, 7 79%, V48
1 answer:
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Answer:
The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 24 - 1 = 23
98% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 23 degrees of freedom(y-axis) and a confidence level of . So we have T = 2.5
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 42 - 1.02 = $40.98.
The upper end of the interval is the sample mean added to M. So it is 42 + 1.02 = $43.02.
The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.
Answer: see image
<u>Step-by-step explanation:</u>
Draw the line y = 1. Count how many units away the point is from that line. Move that point the same number of units in the opposite direction to create the reflection.
J is 2 units above y = 1. The new point is 2 units below y = 1. → (3, -1)
K is 3 units above y = 1. The new point is 3 units below y = 1. → (6, -2)
L is 5 units above y = 1. The new point is 5 units below y = 1. → (3, -4)
M is 3 units above y = 1. The new point is 3 units below y = 1. → (0, -2)
