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never [62]
2 years ago
14

I think of a number. When I add 12 and subtract 8, I get 15. What is that number?

Mathematics
2 answers:
Masja [62]2 years ago
6 0

Answer:

11

Step-by-step explanation:

15 + 8 = 23

23 - 12 = 11

hope it's right

zheka24 [161]2 years ago
3 0

Answer:

11?

Step-by-step explanation:

Hope I'm right! (:

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Step-by-step explanation:

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Fynjy0 [20]

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Step-by-step explanation:


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3 years ago
Read 2 more answers
for a class of 24,78% of students got a B or better on the tex How many students is this? Round to a wholenumber
natita [175]

Step 1

Use the ratio of the number to the percentage to get the required answer.

\frac{Total\text{ number of students}}{\text{The required number of students}}=\frac{Total\text{ percentage of the class}}{\text{Given percentage}}

Where,

\begin{gathered} \text{The total number of students = 24} \\ \text{The required number }of\text{ students= x} \\ \text{The total percentage of the class = 100} \\ \text{Given percentage = 78} \end{gathered}

Step 2

Get the required answer

\begin{gathered} \frac{24}{x}=\frac{100}{78} \\ 100x=24\times78 \\ 100x=1872 \\ \frac{100x}{100}=\frac{1872}{100} \\ x=\text{ 18.72} \\ \text{Hence} \\ x\approx19students\text{ rounded to a whole number } \end{gathered}

The number of students that got B or a better grade on the test = 19 students rounded to a whole number.

4 0
11 months ago
I’ll mark brainlest:( i need help!
enyata [817]

Answer: Choice A)  3 \sqrt{26}

==================================================

Work Shown:

\text{The two points are } (x_1,y_1) = (6,7) \text{ and }  (x_2,y_2) = (3,-8)\\\\d = \text{Distance between } (x_1,y_1) \text{ and } (x_2,y_2)\\\\d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2} = \text{Distance Formula}\\\\d = \sqrt{(6-3)^2+(7-(-8))^2}\\\\d = \sqrt{(6-3)^2+(7+8)^2}\\\\

d = \sqrt{(3)^2+(15)^2}\\\\d = \sqrt{9+225}\\\\d = \sqrt{234}\\\\d = \sqrt{9*26}\\\\d = \sqrt{9}*\sqrt{26}\\\\d = 3\sqrt{26}\\\\

When going from 234 to 9*26, the idea here is to factor where one factor is the largest perfect square possible. That way we can use the rule \sqrt{x*y} = \sqrt{x}*\sqrt{y} to break up the root and simplify.

7 0
3 years ago
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