Find the slope of the line described by 3x + 2y + 1 = 0.
3/2
−2/3
−3/2
−1/2
1 answer:
3x + 2y + 1 = 0
subtract 3x+1 from each side
3x + 2y + 1 - 3x -1= -3x -1
2y = -3x-1
divide by 2 on each side
2y/2 = -3x/2 -1/2
y = -3/2 x -1/2
this is in the form y = mx +b where m is the slope
m = -3/2
the slope is -3/2
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