Using the Normal distribution, it is found that 0.0359 = 3.59% of US women have a height greater than 69.5 inches.
In a <em>normal distribution</em> with mean 
and standard deviation 
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
US women’s heights are normally distributed with mean 65 inches and standard deviation 2.5 inches, hence 
.
The proportion of US women that have a height greater than 69.5 inches is <u>1 subtracted by the p-value of Z when X = 69.5</u>, hence:
has a p-value of 0.9641.
1 - 0.9641 = 0.0359
0.0359 = 3.59% of US women have a height greater than 69.5 inches.
You can learn more about the Normal distribution at brainly.com/question/24663213
Answer:
132cm²
Step-by-step explanation:
You can find the area of the entire shape by calculating the area of seperate smaller shapes.
You can split them up into 2 rectangles, one with a base of 7cm and height of 4cm, and another one with a base of 7cm and height of 8cm. You also have 2 triangles, with a base of 19cm - 7cm / 2 = 6cm since it is the entire bottom line subtracted by the top; they will have a height of 8cm each.
To calculate the rectangles areas, simply do length x width, which are:
4cm x 7cm = 28cm²
8cm x 7cm = 56cm²
Next, since the triangles are similar in measurements, instead of doing the normal calculation to find the area of a triangle, you can do base times height again, which is:
6cm x 8cm = 48cm²
Add all the answers together to get the final area, which is 132cm².
The answer is k=8 (4,6/8,7/12,8)
0.5! This can be explained because 1/2 x 1/2 is equal to 0.25 so if we add another 0.25, it will be 0.5
