Answer:
A soap or alcohol will interfere with the hydrogen bonding between water molecules making it weaker
Explanation:
A water molecule is polar as the oxygen atom is strongly electronegative and draws the electrons it shares with the hydrogen atoms in the water molecule to itself. This creates a partial negative charge on the oxygen atom and partial positive charges on the hydrogen atoms. The attraction of neighboring oxygen to hydrogen atoms in a water molecule results in hydrogen bonding.
However, a detergent molecule which has a polar head and a hydrophobic tail, when added to water significantly interferes with the hydrogen bonding between water molecules. The polar head is attracted to water molecules whereas the hydrophobic tail of each molecule are not. The detergent molecules form clusters known as micelles with the polar heads attracted to water and the hydrophobic tails directed towards the center of the micelle, away from water molecules. This weakens the hydrogen bonding between water molecules
An alcohol contains a polar -OH group in its molecules. However, the hydrogen bonding between alcohol molecules are weaker than that in water because the other end of the alcohol molecule has a C-O bond which is less polar than the O-H bond. Therefore, when an alcohol is added to water, it weakens the hydrogen bonding in water.
This weakening of the hydrogen bonding in water also has the effect of lowering the surface tension of water.
2C4H10 + 13O2 Right arrow. 8CO2 + 10H2O
What is the mole ratio of butane to carbon dioxide?
ANSWER:
Butane is an organic compound with the formula C4H10 and carbon dioxide is compound (gas) with the formula CO2. So, the balanced coefficient of butane is 2, and that of carbon dioxide is 8. According to thid, the mole ratio of butane to carbon dioxide is 2:8 or 1:4.
Answer:
50?
I think but not 100% sure if not lmk
Copper (Cu) and silver (Ag) would not liberate hydrogen because they are less reactive than hydrogen since their standard reduction potential is higher.
Answer:
Equilibrium Constant = (3.60 × 10⁶²)
Explanation:
The change in Gibb's free energy for a galvanic cell is given as
Δ = -nFE°
where n = number of electrons transferred = 5 for this reaction
F = Faraday's constant = 96500 C
E° = cell potential = +0.74 V
But the change in Gibb's free energy for galvanic cell reaction is also given as
ΔG = -RT In K
R = molar gas constant = 8.314 J/mol.K
T = absolute temperature in Kelvin = 25 + 273.15 = 298.15 K
K = Equilibrium constant.
Equating these two expressions
-nFE° = - RT In K
RT In K = nFE°
In K = (nFE°) ÷ (RT)
In K = (5 × 96500 × 0.74) ÷ (8.314 × 298.15)
In K = 144.04
K = e^(144.04)
K = (3.60 × 10⁶²)
Hope this Helps!!!
