Question

Please help with these two chemistry questions. Image attached.

Answer 1

The answers for the following questions is answered below.

• Therefore the volume of a gas is 22.4 L

• Therefore the number of moles of oxygen are 2.37 moles

Explanation:

1. Given:

no of molecules (n) = 6.023 × $10^{23}$

volume of gas at STP conditions (V) =22.4 liters

To solve:

Volume of gas (v)

We know;

$\frac{n}{N_{a} } =\frac{v}{V}$

$\frac{6.023 * 10^{23} }{6.023 * 10^{23} } =\frac{v}{22.4}$

1 × 22.4 = v

v =22.4 L

Therefore the volume of a gas is 22.4 L

2. Given:

volume of oxygen gas (v) = 53 L

Volume of gas at STP conditions (V) =22.4 L

To solve:

no of moles of oxygen gas

We know;

$n =\frac{v}{V}$

n =$\frac{53}{22.4}$

n =2.37 moles

Therefore the number of moles of oxygen are 2.37 moles