Answer:
Q < K for both reactions. Both are spontaneous at those concentrations of substrate and product.
Explanation:
Hello,
In this case, the undergoing chemical reactions with their proper Gibbs free energy of reaction are:


The cellular concentrations are as follows: [A] = 0.050 mM, [B] = 4.0 mM, [C] = 0.060 mM and [D] = 0.010 mM.
For each case, the reaction quotient is:

A typical temperature at a cell is about 30°C, in such a way, the equilibrium constants are:

Therefore, Q < K for both reactions. Both are spontaneous at those concentrations of substrate and product.
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Answer:
HNO₃.
Explanation:
- It is known that acids decrease the pH of the solution, while bases increase the pH of the solution.
So, HF and HNO₃ decrease the pH of the solution as they produce H⁺ in the solution.
While, KOH and NH₃ increase the pH of the solution as they produce OH⁻ in the solution.
HNO₃ will decrease the pH of the solution greater than HF.
- Because HNO₃ is strong acid that decomposes completely to produce H⁺ more than the same concentration of HF that is a weak acid which does not decomposed completely to produce H⁺.
I read and said it's a weak base
B and C are in excess so amount of E will be determined by A.
Amount of product is determined by limiting reagents - Always.
Hence 6 moles of E will be formed.
Hope this helps!