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fiasKO [112]
3 years ago
12

What mass of water will change its temperature by 3.0 0C when 525 J of heat is added to it? The specific heat of water is 4.184

J/g 0C.
Chemistry
1 answer:
pav-90 [236]3 years ago
4 0

Answer:

Mass of water = 41.8 g

Explanation:

Given data:

Mass of water = ?

Change in temperature = 3.0 °C

Specific heat capacity = 4.184 j/g.°C

Heat absorbed = 525 j

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 3.0°C

Now we will put the values in formula.

525 J = m × 4.184 j/g.°C  × 3.0°C

525 J = m × 12.552 j/g

m =  525 J/ 12.552 j/g

m = 41.8 g

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The following are the steps  to complete and balnce the equation for the given reaction

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NO2– -----> NO3– ………oxidation half reaction

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Step 3) Balance the O by adding 1 H2O for 1 O

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Step 4) Balance the H by adding H+

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