Answer:
B. l = (S - πr^2) / πr
Step-by-step explanation:
S = πrl + πr^2 solve for l
πrl = S - πr^2
l = (S - πr^2) / πr
Answer is B. l = (S - πr^2) / πr
Answer:
<h2>2/5</h2>
Step-by-step explanation:
The question is not correctly outlined, here is the correct question
<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>
Given data
Total students in class= 35 students
Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so
|M ∪ N|= 35-12= 23
|M∩N|= |M|+N- |MUN|= 17+20-23
=37-23=14
So the probability that a random student is both a junior and social science major is
=P(M∩N)= 14/35
=2/5
Answer:
-7×-9
=63
Step-by-step explanation:
If u multiple - with -, I'll get + sign
Answer:
2.2
Step-by-step explanation:
This is because you can use long divison on paper, 25 goes in 50 2 times so it would be remaining with 5 and since you need no remainers bring down a zero which gives you an extra 50 and 25 goes in 50 2 times so 2.2
To work it out:
(20200 + 14500 + 18800 + 9300 + 2200) divide by the number of regions, in this case 5.
The answer is 13000 which is A
Basically the mean is adding all the numbers divided by the amount of numbers you added. So in this case adding the data of the 5 regions divided by 5.
Hope to have helped :)
