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crimeas [40]
2 years ago
12

Please help me ! !!!

Mathematics
1 answer:
Kruka [31]2 years ago
8 0
3 that’s the answer your welcome
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Factor out the GCF -2x^2 - 4x - 6
andrew-mc [135]

The Greatest Common factor(GCF) of -2x^2-4x-6 is -2(x+1)(x-3)

<h3>What is Greatest Common Factor?</h3>

The greatest common factor (GCF) is the largest factor two or more numbers have in common

From the question,

-2x^2-4x-6

By collecting like terms

-2(x^2-2x-3)

By factoring x^2-2x-3

-2(x^2-3x+1x-3)

Collecting like terms

-2(x^2-3x)+(x-3)

-2(x(x-3)+1(x-3))

-2(x+1)(x-3)

hence  -2(x+1)(x-3) is the Greatest Common factor of  -2x^2-4x-6 is

Learn more about Greatest Common factor on:brainly.com/question/219464

#SPJ1

3 0
11 months ago
If a bookworm can finish eating 23.68 pages of a book in 3.2 days, how much can it eat in
blagie [28]

Answer:

7.4

Step-by-step explanation:

just divide it by 3.2

4 0
3 years ago
What is the combined perimeter of these two rectangles?
GarryVolchara [31]

Answer:

D) 24x + 52

Step-by-step explanation:

The perimeter of the purple rectangle is

P =2(l+w)

   =2 (4x+5  + 2x+7)

Combine like terms

   =2 (6x+12)

Distribute

  = 12x +24

The perimeter of the white rectangle is

P =2(l+w)

P =2(3x+14 +3x)

Combine like terms

  =2(6x+14)

Distribute

 12x +28

Add the perimeters

12x +24 +  12x +28

24x +52

5 0
3 years ago
Read 2 more answers
The trigonometric ratios sine and secant are reciprocals of each other true or false?
kodGreya [7K]

True: The trigonometric ratios sine and secant are reciprocals of each other

7 0
3 years ago
Read 2 more answers
A function f(x)=3x+12.
seraphim [82]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2822258

_______________


•  Function:   f(x) = 3x + 12.


A.  Finding the inverse of f.

The composition of f with its inverse results in the identity function:

(f o g)(x) = x

f[ g(x) ] = x

3 · g(x) + 12 = x

3 · g(x) = x – 12

              x – 12
g(x)  =  ⸺⸺
                 3

               x 
g(x)  =  ⸺  –  4    <———    this is the inverse of f.
               3

________


B.  Verifying that the composition of f and g gives us the identity function:

•  \mathsf{(f\circ g)(x)}

\mathsf{=f\big[g(x)\big]}\\\\\\ \mathsf{=3\cdot \left(\dfrac{x}{3}-4\right)+12}\\\\\\&#10;\mathsf{=\diagup\hspace{-7}3\cdot \dfrac{x}{\diagup\hspace{-7}3}-3\cdot 4+12}\\\\\\&#10;\mathsf{=x-12+12}\\\\&#10;\mathsf{=x\qquad\quad\checkmark}


and also

•  \mathsf{(g\circ f)(x)}

\mathsf{=g\big[f(x)\big]}\\\\\\ \mathsf{=\dfrac{f(x)}{3}-4}\\\\\\ \mathsf{=\dfrac{3x+12}{3}-4}\\\\\\&#10;\mathsf{=\dfrac{\diagup\hspace{-7}3\cdot (x+4)}{\diagup\hspace{-7}3}-4}\\\\\\&#10;\mathsf{=x+4-4}\\\\&#10;\mathsf{=x\qquad\quad\checkmark}

________


C.  Since f and g are inverse, then

f(g(– 2))

= (f o g)(– 2)

= – 2          <span>✔
</span>

•  Call h the compositon of f and g. So,

h(x) = (f o g)(x)

h(x) = x


As you can see above, there is no restriction for h. Therefore, the domain of h is R (all real numbers).


I hope this helps. =)

5 0
3 years ago
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