All categories

3 years ago

Please help me ASAP!!!!!!!!!

Chemistry

1 answer:

padilas [110]3 years ago

6 0

Explanation:

chemical analysis of a compound shows that it contains 0.99g lead ,0.154g sulfur and 0.306g oxygen. what is the empirical formula of the compound.

You might be interested in

How many ml of 12.0 M H2S04 are needed to make 500.0 ml of a 1.00 M solution? What happens to the freezing point and the boiling

lora16 [44]

Answer:

41.66 mL of 12.0 M sulfuric acid are needed.

Explanation:

Concentration of sulfuric acid solution taken = $M_1=12.0M$

Volume of the 12.0 M Solution = $V_1$

Concentration of required solution = $M_2=1.00M$

Volume of required 1.00 M solution = $V_2=500.0 mL$

$M_1V_1=M_2V_2$ (Dilution)

$V_1=\frac{1.00 M\times 500.0 mL}{12.0 M}=41.66 mL$

41.66 mL of 12.0 M sulfuric acid are needed.

The freezing point and the boiling point of a solvent when a non-volatile solute is dissolved in it decrease and increase respectively.

3 0

4 years ago

What amount of SeC16 is needed to produce 4.45 mol of chlorine gas in the

AlladinOne [14]

Answer:

1.48 moles of SeCl6 are needed

Explanation:

Based on the reaction:

SeCl6 + O2 → SeO2 + 3Cl2

<em>1 mole of SeCl6 reacts producing 3 moles of Cl2.</em>

To solve this question we need to use the conversion factor:

1mol SeCl6 = 3mol Cl2

As we want to produce 4.45 moles of Cl2, we need:

4.45 mol Cl2 * (1mol SeCl6 / 3mol Cl2) =

<h3>1.48 moles of SeCl6 are needed</h3>

6 0

3 years ago

Who wanna become my bestfriend nd maybe more??? id.k im just bored

olasank [31]

Answer:

Hello

Explanation:

5 0

3 years ago

Read 2 more answers

What is the volume of a salt crystal measuring 1.64 x 10^-2m by 1.5 x 10^-2m by 4.8 x 10^-3

lubasha [3.4K]

Answer:

V = 1.2 × 10⁻⁶ m³

Explanation:

Volume is equal to length × width × height, since we are given these measurements in the question we can simply plug our numbers into the formula.

V = l × w × h

V = 1.64 x 10⁻² × 1.5 x 10⁻² × 4.8 x 10⁻³

V = 1.2 × 10⁻⁶ m³

5 0

4 years ago

A gas is contained in a thick-walled balloon. When the pressure changes from 39.1 bar to 87.0 bar the volume changes from blank

lidiya [134]

Answer: -

1.34 L

Explanation: -

Initial Pressure P 1 = 39.1 bar

Initial Temperature T 1 = 643 K

Let the initial volume be V 1.

Final pressure P 2 = 87.0 bar

Final temperature T 2 = 525 K.

Final volume V 2 = 0.492 L

Using the equation

$\frac{P1 V 1}{T1} = \frac{P 2 V 2}{T2}$

$V 1 = \frac{P2 V2 T1}{P 1 T2}$

Plugging in the values

We have

V 1 = 87 bar x 0.492 L x 643 K / (39.1 bar x 525 K)

= 1.34 L

Thus, a gas is contained in a thick-walled balloon. When the pressure changes from 39.1 bar to 87.0 bar the volume changes from 1.34 L to 0.492L and the temperature changes from 643K to 525K

4 0

4 years ago

Read 2 more answers