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3 years ago

Please help me ASAP!!!!!!!!!

Chemistry

1 answer:

padilas [110]3 years ago

6 0

Explanation:

chemical analysis of a compound shows that it contains 0.99g lead ,0.154g sulfur and 0.306g oxygen. what is the empirical formula of the compound.

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A precipitate forms when mixing solutions of sodium fluoride (NaF) and lead II nitrate (Pb(NO3)2). Complete and balance the net

Margarita [4]

Answer:

Pb^2+(aq) + 2F-(aq) → PbF2(s)

Explanation:

Step 1: Data given

sodium fluoride = NaF

lead(II)nitrate Pb(NO3)2

Step 2: The unbalanced equation

NaF(aq) + Pb(NO3)2(aq) → PbF2(s) + NaNO3(aq)

Step 3: Balancing the equation

NaF(aq) + Pb(NO3)2(aq) → PbF2(s) + NaNO3(aq)

On the left side we have 2x NO3 (in Pb(NO3)2), on the right side we have 1x NO3 (in NaNO3). To balance the amount of NO3 we hvae to multiply NaNO3 on the right side by 2.

NaF(aq) + Pb(NO3)2(aq) → PbF2(s) + 2NaNO3(aq)

On the left side we have 1x Na (in NaF), on the right side we have 2x Na (in 2NaNO3). To balance the amount of Na we have to multiply NaF on the left side by 2. Now the equation is balanced.

2NaF(aq) + Pb(NO3)2(aq) → PbF2(s) + 2NaNO3(aq)

Step 4: Calculate net ionic equation

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will , after canceling those spectator ions in both side, look like this:

2Na+(aq) + 2F-(aq) + Pb^2+(aq) + 2NO3-(aq) → PbF2(s) + 2Na+(aq) + NO3-(aq)

Pb^2+(aq) + 2F-(aq) → PbF2(s)

4 0

3 years ago

Zinc reacts with iodine in a synthesis reaction: Zn + I2 → Znl2. What is the theoretical yield of Znl2, if 1.912 mol of zinc is

lawyer [7]

Answer:

610.3g

Explanation:

Zn:

m = 1.912

Zn : ZnI₂

1 : 1

1.912 : 1.912

ZnI₂:

m = 1.912 Mr = 65.4 + 2(126.9) = 319.2

mass = m×Mr:

mass = 1.912×319.2

mass = 610.3104 → 610.3g

3 0

3 years ago

Part 1: A cylinder containing 20.0 L of compressed nitrogen is connected to an empty (evacuated) vessel with an unknown volume.

baherus [9]

Answer:

The volume of the vessel is 250 L

Partial pressure of hydrogen = 189 torr

Explanation:

Using Boyle's law

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,

V₁ = 20.0 L

V₂ = ?

P₁ = 25 atm

P₂ = 2 atm

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${25}\times {20.0}={2}\times {V_2}$

${V_2}=\frac {{25}\times {20.0}}{2}\ L$

${V_2}=250\ L$

<u>The volume of the vessel is 250 L.</u>

According to Dalton's law of partial pressure:-

$P_{H_2}=Mole\ fraction\times Total\ Pressure$

So, according to definition of mole fraction:

$Mole\ fraction\ of\ H_2=\frac {n_{H_2}}{n_{H_2}+n_{He}}$

Also,

Mole fraction of H₂ = 1 - Mole fraction of He = 1 - 0.75 = 0.25

So,

Total pressure = 756 torr

Thus,

$P_{H_2}=0.25\times 756\ torr$

<u>Partial pressure of hydrogen = 189 torr.</u>

7 0

3 years ago

What is the formula for the compound iodine trichoride?

Serjik [45]

Answer:I2Cl6

Explanation:

5 0

3 years ago

What volume of nitrogen gas at STP is produced when 68.2 g of trinitrotoluene, C7H5(NO2)3 reacts?

lys-0071 [83]

Answer:

10.07 L is the volume for the produced N₂

Explanation:

This is a question for the Ideal Gases Equation:

P . V = n . R . T

In STP conditions, the pressure is 1 atm and the T° is 273K

Let's determine the moles of produced N₂ by the decomposition of TNT

The reaction is:

2 C₇H₅(NO₂)₃ (s) → 7 C (s) + 7 CO (g) + 3 N₂ (g) + 5 H₂O (g)

We convert the mass to moles (mass / molar mass)

68.2 g . 1 mol / 227.13 g = 0.300 moles

Ratio is 2:3. 2 moles of TNT can produce 3 moles of N₂

Then, 0.300 moles will produce (0.300 . 3) / 2 = 0.450 moles

We replace data:

1 atm . V = 0.450 mol . 0.082 L.atm/mol.K . 273K

V = (0.450 mol . 0.082 L.atm/mol.K . 273K) / 1 atm

V = 10.07 L

4 0

4 years ago