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2 years ago

Given the equation-4x+2y=-2 what is the slope of a line parallel to the line?

Mathematics

1 answer:

Svetach [21]2 years ago

3 0

Answer:

The equation of the perpendicular line would be y = -1/2x - 1

Step-by-step explanation:

In order to find this line, we must first find the slope of the original line. We do this by solving for y.

-4x + 2y = 2

2y = 4x + 2

y = 2x + 1

This shows us a slope of 2. TO find the perpendicular slope, we use the opposite and reciprocal. This means we negative 2 to get -2 and then we flip it to get -1/2. Now that we have this, we can use the slope and the point in point-slope form to get the equation.

y - y1 = m(x - x1)

y + 2 = -1/2(x - 2)

y + 2 = -1/2x + 1

y = -1/2x - 1

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What's the domain and range for (×+4)-1

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$\bf a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad

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3 years ago

Direct and Indirect Proportions

ivanzaharov [21]

Answer:

Step-by-step explanation:

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2 years ago

Instructions: Select the correct answer from each drop-down menu.

vovangra [49]

Answer: The answer is (A) $\dfrac{4}{3}.$ and (C) $4x-3y=0.$

Step-by-step explanation: We are given a graph with a point A having co-ordinates (3, 4) and origin O(0, 0). We are to find the slope and equation of line OA.

Since O(0, 0) and A(3, 4) are two points on the line OA, so its slope will be

$m=\dfrac{4-0}{3-0}=\dfrac{4}{3}.$

And the equation of the line will be

$y-0=\dfrac{4}{3}(x-0)\\\\\\\Rightarrow y=\dfrac{4}{3}x\\\\\\\Rightarrow 3y=4x\\\\\Rightarrow 4x-3y=0.$

Thus, the correct options are (A) and (C).

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2 years ago

What is the equation of the line that has a slope of 3 and passes through the point (1,-2)?

Vera_Pavlovna [14]

Answer:

y = 3x - 5

Step-by-step explanation:

y = mx + b

y - b = mx

-b = mx - y

b = -mx + y

b = -3(1) -2

b = -5

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2 years ago