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3 years ago

Please help solve the for x. I'm offering 20 points

Mathematics

1 answer:

andrew11 [14]3 years ago

3 0

Answer:

1/-21

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−1

=6x

Step 2: Subtract 6x from both sides.

−1

−6x=6x−6x

−7

−1

Step 3: Add 1/12 to both sides.

−7

−1

=0+

−7

Step 4: Multiply both sides by 4/(-7).

(

−7

)*(

−7

x)=(

−7

)*(

)

−1

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Solve (x + 1)2 – 4(x + 1) + 2 = 0 using substitution.

solniwko [45]

For this case we have to:

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So:

$u ^ 2-4u + 2 = 0$

We have the solution will be given by:

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Where:

$a = 1\\b = -4\\c = 2$

Substituting:

$u = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (2)}} {2 (1)}\\u = \frac {4 \pm \sqrt {16-8}} {2}\\u = \frac {4 \pm \sqrt {8}} {2}\\u = \frac {4 \pm \sqrt {2 ^ 2 * 2}} {2}\\u = \frac {4 \pm2 \sqrt {2}} {2}$

The solutions are:

$u_ {1} = \frac {4 + 2 \sqrt {2}} {2} = 2 + \sqrt {2}\\u_ {2} = \frac {4-2 \sqrt {2}} {2} = 2- \sqrt {2}$

Returning the change:

$2+ \sqrt {2} = x_ {1} +1\\x_ {1} = 1 + \sqrt {2}\\2- \sqrt {2} = x_ {2} +1\\x_ {2} = 1- \sqrt {2}$

Answer:

$x_ {1} = 1 + \sqrt {2}\\x_ {2} = 1- \sqrt {2}$

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Ulleksa [173]

Answer:

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Step-by-step explanation:

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2 years ago

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slavikrds [6]

Ye, np.

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2 years ago

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shutvik [7]

Answer:

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Step-by-step explanation:

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