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Romashka-Z-Leto [24]
3 years ago
15

Which expression is equivalent to 5^3√6c+7^3√6c, if c ≠ 0

Mathematics
1 answer:
scZoUnD [109]3 years ago
4 0

Answer:

Option C

Step-by-step explanation:

complete question

A. 35[3]6cB. 12[3]12cC. 12[3]6cD.72c

The given equation can be written as

5^3√6c+7^3√6c

5 * \sqrt{3 *3*2c} + 7 * \sqrt{3 *3*2c}

5 * 3 *\sqrt{2c} + 7 * 3  *\sqrt{2c}

15  *\sqrt{2c} + 21 *\sqrt{2c}

36 *\sqrt{2c}

12 [3]*\sqrt{2c}

Option C is correct

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A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
d^2=3^2+2^2
d^2=9+4
d^2=13
d= \sqrt{13}
We can conclude that the distance between my house and the movie theater is \sqrt{13}

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
d^2=6^2+5^2
d^2=36+25
d^2=61
d= \sqrt{61}
We can conclude that the distance between the police station and the airport is \sqrt{61}

C. Distance form the park to the Fire Station:
d^2=3^2+1^2
d^2=9+1
d^2=10
d= \sqrt{10}
We can conclude that the distance from the park to the Fire Station is \sqrt{10}

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d^2=2^2+1^2
d^2=4+1
d^2=5
d= \sqrt{5}
We can conclude that the distance from the stadium to the mall is \sqrt{5}

D. What is the distance between your house and the mall?
Answer:
d^2=4^2+4^2
d^2=16+16
d^2=32
d= \sqrt{32}
d=4 \sqrt{2}
We can conclude that the distance between my house and the mall is 4 \sqrt{2}

What is the distance between the movie theater and the school?
answer:
d^2=3^2+1^2
d^2=9+1
d^2=10
d= \sqrt{10}
We can conclude that the distance between the movie theater and the school is \sqrt{10}

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3 years ago
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