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3 years ago

When you multiple 2/3 by a fraction less than one, how does the product compare to the fraction?Explain

Mathematics

1 answer:

pentagon [3]3 years ago

7 0

Thanks for the question!

It will be less than the fraction.

Hope this helps!

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Find the area of each sector. Round your answers to the nearest tenth.

nata0808 [166]

Answer:

Area of sector = 102.6 feet squared

Step-by-step explanation:

Given:

Radius of circle = 14 ft

Angle θ = 60°

Find:

Area of sector

Computation:

Area of sector = [θ/360]πr²

Area of sector = [60/360](22/7)(14)²

Area of sector = [1/6][22/7][196]

Area of sector = 102.6 feet squared

3 0

2 years ago

The function y = 50x describes the distance Gary has traveled in miles after x hours. Use the graph to estimate how many miles G

Nana76 [90]

Substitute 8 for x in the function.
y=50(8)=400
He would travel 400 miles

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2 years ago

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Simplify: −3xy2(2x2y3 + 7xy2 − 5x3y2)

mestny [16]

collect the like terms

Answer is C

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2 years ago

Write an inequality (you must be older than 13 to play basketball league

marshall27 [118]

13+x=x because 13 plus x will be a good number so you can be able to join the basketball league

4 0

3 years ago

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Help !! Please I can’t find the answer

SVETLANKA909090 [29]

Answer:

$\large\boxed{r^2=(x+5)^2+(y-4)^2}$

Step-by-step explanation:

The equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have diameter endpoints.

Half the length of the diameter is the length of the radius.

The center of the diameter is the center of the circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the given points (-8, 2) and (-2, 6):

$d=\sqrt{(6-2)^2+(-2-(-8))^2}=\sqrt{4^2+6^2}=\sqrt{16+36}=\sqrt{52}$

The radius:

$r=\dfrac{d}{2}\to r=\dfrac{\sqrt{52}}{2}$

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-2)}{2}=\dfrac{-10}{2}=-5\\\\y=\dfrac{2+6}{2}=\dfrac{8}{2}=4$

$(-5,\ 4)\to h=-5,\ k=4$

Finally:

$(x-(-5))^2+(y-4)^2=\left(\dfrac{\sqrt{52}}{2}\right)^2\\\\(x+5)^2+(y-4)^2=\dfrac{52}{4}\\\\(x+5)^2+(y-4)^2=13$

5 0

3 years ago