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3 years ago

Plot the zeros of this function: f(x) = (x – 1)(x – 7).

Mathematics

1 answer:

vredina [299]3 years ago

5 0

Answer:

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Step-by-step explanation:

The zeros of a function is where the function crosses the x-axis. The x-intercepts are the zeros of a function.

$f(x) = (x - 1)(x - 7)$

Let output equal to 0.

$0 = (x - 1)(x - 7)$

Set factors equal to 0.

$x-1=0\\x=1$

$x-7=0\\x=7$

The zeros of the function are $x=1$ and $x=7$ .

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Given the linear equation y = 10x - 11.

grigory [225]

Y 10x - 13 should be right

4 0

3 years ago

If there were 49 cars in a line that stretched 528 feet, what is the average car length? assume that the cars are lined up bumpe

lakkis [162]

If there were 49 cars in a line that stretched 528 feet, what is the average car length? assume that the cars are lined up bumper-to-bumper

Answer: We are given there are 49 cars

Also these 49 cars are in a line stretched 528 feet.

Now the average length of the car is:

Average length = $\frac{(length-covered-by-49-cars)}{Number-of-cars}$

= $\frac{528}{49}=10.78$

Therefore, the average length of car is 10.78 feet

6 0

3 years ago

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

3 years ago

Monthly sales of an SUV model are expected to increase at the rate of S′1t2 = -24t 1>3 SUVs per month, where t is time in mon

uysha [10]

The company will continue to manufacture this model for 19 months.

The question is ill-formatted. The understandable format is given below.

An SUV model's monthly sales are anticipated to rise at a rate of

$S'(t)=-24^{1/3}$ SUVs each month, where "t" denotes the number of months and "S(t)" denotes the monthly sales of SUVs. When monthly sales of 300 SUVs are reached, the business intends to discontinue producing this model.