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Vaselesa [24]
2 years ago
8

What is the circumference of a circle with a diameter of 62 centimeters?

Mathematics
1 answer:
devlian [24]2 years ago
4 0

Answer:

The Answer is 62π or 194.77874452256718078468388976333.

Step-by-step explanation: To find the circumference of a circle, you need to multiply the diameter by π. The equation is 2πr.

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Which equation can be used to solve for x in the following diagram.
Leokris [45]
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6 0
3 years ago
What is the estimate of 824 ÷ 42
Fiesta28 [93]

Answer:34.333 repeating

Step-by-step explanation:

8 0
3 years ago
The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
Mama L [17]

Answer:

a) P(Y > 76) = 0.0122

b) i) P(both of them will be more than 76 inches tall) = 0.00015

   ii) P(Y > 76) = 0.0007

Step-by-step explanation:

Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.

To find - (a) If a man is chosen at random from the population, find

                    the probability that he will be more than 76 inches tall.

              (b) If two men are chosen at random from the population, find

                    the probability that

                    (i) both of them will be more than 76 inches tall;

                    (ii) their mean height will be more than 76 inches.

Proof -

a)

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{S.D}) > \frac{( 76- mean)}{S.D})

                 = P(Z >  \frac{( 76- mean)}{S.D})

                 = P(Z > \frac{76 - 69.7}{2.8})

                 = P(Z > 2.25)

                 = 1 - P(Z  ≤ 2.25)

                 = 0.0122

⇒P(Y > 76) = 0.0122

b)

(i)

P(both of them will be more than 76 inches tall) = (0.0122)²

                                                                           = 0.00015

⇒P(both of them will be more than 76 inches tall) = 0.00015

(ii)

Given that,

Mean = 69.7,

\frac{S.D}{\sqrt{N} } = 1.979899,

Now,

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{\frac{S.D}{\sqrt{N} } })) > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- 69.7)}{1.979899 }))

                 = P(Z > 3.182)

                 = 1 - P(Z ≤ 3.182)

                 = 0.0007

⇒P(Y > 76) = 0.0007

6 0
3 years ago
Can someone help me with this please !!
pogonyaev

add all amd divide by the 40 ???let me know if im wrong

7 0
3 years ago
Read 2 more answers
Divide (12n^3+8n^2-6n)/2n^2
nexus9112 [7]
\frac{12n^{3} + 8n^{2} - 6n}{2n^{2}} = \frac{12n^{3}}{2n^{2}} + \frac{8n^{2}}{2n^{2}} - \frac{6n}{2n^{2}} = 6n + 4 - \frac{3}{n}
8 0
3 years ago
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