A stadium has central rectangular area 125m long by 80 m wide there are two semicircular ends.running tracks goes all way round
1 answer:
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Answer:
31.4 in³
Step-by-step explanation:
The box is just big enough to hold the 3 balls, so it must have a length 6 times the radius of each ball, a width 2 times the radius, and a height 2 times the radius.
The volume of the box is:
V = (6r)(2r)(2r)
V = 24r³
The volume of the 3 balls is:
V = 3 (4/3 π r³)
V = 4πr³
So the volume of the air is:
V = 24r³ − 4πr³
V = (24 − 4π) r³
Since r = 1.4 inches:
V = (24 − 4π) (1.4 in)³
V ≈ 31.4 in³
Answer:
Step-by-step explanation:
Whe have the function
To solve this equation we must factor.
To factor, we need to find the points where the function is equal to zero. So we use the quadratic formula
Where:
a = 3
b = -6
c = 2
Then
finally the correct answer is