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dexar [7]
3 years ago
6

A stadium has central rectangular area 125m long by 80 m wide there are two semicircular ends.running tracks goes all way round

Mathematics
1 answer:
olga_2 [115]3 years ago
7 0

) Using formula for cicumference.

Circumference = Pi * diameter

Circumference = Pi * 80m

Circumference = 251.2m.

Total inside length of the curved ends.

2)Total distance round inside of track =

2(125) + 251.2m

= 250 + 251.2

= 501.2m

3) Area of circular ends =

Pi*r^2

= Pi*40^2

= 5024m^2

Area of central area (rectangle)

length * width

125m * 80m

= 10,000m^2

Total area inside track =

5,024m^2 + 10,000m^2

= 15,024m^2

Hope this helps.

:-)

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The area of the triangle EFG is 7.4 square units.

Explanation:

Given that the measurements of the sides of the triangle are EF = 8, EG = 8 and m\angle E=22^{\circ}

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<u>Area of the triangle:</u>

The area of the triangle EFG can be determined using the formula,

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