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jolli1 [7]
3 years ago
15

Multiply (x-4)(x^2-5x-6) ...?

Mathematics
2 answers:
Inga [223]3 years ago
7 0

Answer:

<em>The answer is:  x^3-9x^2+14x+24</em>

Step-by-step explanation:

The given expression is:  (x-4)(x^2-5x-6)

For getting the product, <u>we need to distribute (x-4) with each term in the second parenthesis</u>. So.....

(x-4)(x^2-5x-6)\\ \\ =x^2(x-4)-5x(x-4)-6(x-4)\\ \\ =x^3-4x^2-5x^2+20x-6x+24 \ [using\ distribution\ rule]\\ \\ =x^3-9x^2+14x+24\ [combining\ like\ terms]

So, the answer is:  x^3-9x^2+14x+24

frez [133]3 years ago
6 0
See attached photo for answer.

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Write this ratio as a fraction in simplest form without any units. 56 hours to 2 days
Svetllana [295]

Answer:

28

Step-by-step explanation:

56/2 = 38

8 0
2 years ago
One fifth of the sum of 9 and h
8090 [49]

Answer:

= (9 + h) /5

Step-by-step explanation:

One fifth  means 1/5

Sum of 9 and h = (9 +h)

One fifth of sum of 9 and h = 1/5 x (9 + h)

= (9 + h) /5

I hope this was helpful, Please mark as brainliest

8 0
3 years ago
15 POINTS ANSWER ASAP, SHOW WORK
forsale [732]

Answer:

V=97.6\ in^3

Step-by-step explanation:

step 1

Find the volume of the cylinder

The volume of the cylinder is equal to

V=\pi r^{2}h

we have

r=4/2=2\ in ---> the radius is half the diameter

h=8\ in

substitute

V=\pi (2)^{2}(8)\\\\V=32\pi\ in^3

step 2

Find the volume of the cone

The volume of the cone is equal to

V=\frac{1}{3}\pi r^{2} h

we have

we have

r=2\ in ---> the radius is the same that the radius of the cylinder

h=0.70\ in

substitute

V=\frac{1}{3}\pi (2)^{2} (0.70)\\\\V=0.93\pi\ in^3

step 3

Find the volume of the plastic object

we know that

The volume of the plastic object is equal to the volume of the cylinder minus the volume of the cone

so

V=32\pi-0.93\pi=31.07\pi\ in^3

assume

\pi=3.1416

V=31.07(3.1416)=97.6\ in^3

8 0
2 years ago
Which is a correct two column proof. Given &lt;4 and
vladimir1956 [14]

The initial statement is:    QS = SU   (1)

                                    QR = TU    (2)

 

We have to probe that:  RS = ST

 

 

Take the expression (1):                     QS       =   SU

We multiply both sides by R                (QS)R   =   (SU)R

 

 

But    (QS)R = S(QR)     Then:            S(QR)   =   (SU)R     (3)

 

From the expression (2):  QR = TU. Then, substituting it in to expression (3):

 

                                                       S(TU)   =   (SU)R     (4)

 

But  S(TU) = (ST)U  and (SU)R = (RS)U

 

Then, the expression (4) can be re-written as:

 

                                                      (ST)U    =    (RS)U

 

Eliminating U from both sides you have:     (ST) = (RS)    The proof is done.

4 0
3 years ago
Ok need help please help Thank you
Step2247 [10]
96 1/2 

there is ur answer i think :)
7 0
3 years ago
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