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3 years ago

Multiply (x-4)(x^2-5x-6) ...?

Mathematics

2 answers:

Inga [223]3 years ago

7 0

Answer:

<em>The answer is: $x^3-9x^2+14x+24$ </em>

Step-by-step explanation:

The given expression is: $(x-4)(x^2-5x-6)$

For getting the product, <u>we need to distribute $(x-4)$ with each term in the second parenthesis</u>. So.....

$(x-4)(x^2-5x-6)\\ \\ =x^2(x-4)-5x(x-4)-6(x-4)\\ \\ =x^3-4x^2-5x^2+20x-6x+24 \ [using\ distribution\ rule]\\ \\ =x^3-9x^2+14x+24\ [combining\ like\ terms]$

So, the answer is: $x^3-9x^2+14x+24$

frez [133]3 years ago

6 0

See attached photo for answer.

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Write this ratio as a fraction in simplest form without any units. 56 hours to 2 days

Svetllana [295]

Answer:

Step-by-step explanation:

56/2 = 38

8 0

3 years ago

One fifth of the sum of 9 and h

8090 [49]

Answer:

= (9 + h) /5

Step-by-step explanation:

One fifth means 1/5

Sum of 9 and h = (9 +h)

One fifth of sum of 9 and h = 1/5 x (9 + h)

= (9 + h) /5

I hope this was helpful, Please mark as brainliest

8 0

3 years ago

15 POINTS ANSWER ASAP, SHOW WORK

forsale [732]

Answer:

$V=97.6\ in^3$

Step-by-step explanation:

step 1

Find the volume of the cylinder

The volume of the cylinder is equal to

$V=\pi r^{2}h$

we have

$r=4/2=2\ in$ ---> the radius is half the diameter

$h=8\ in$

substitute

$V=\pi (2)^{2}(8)\\\\V=32\pi\ in^3$

step 2

Find the volume of the cone

The volume of the cone is equal to

$V=\frac{1}{3}\pi r^{2} h$

we have

$r=2\ in$ ---> the radius is the same that the radius of the cylinder

$h=0.70\ in$

substitute

$V=\frac{1}{3}\pi (2)^{2} (0.70)\\\\V=0.93\pi\ in^3$

step 3

Find the volume of the plastic object

we know that

The volume of the plastic object is equal to the volume of the cylinder minus the volume of the cone

$V=32\pi-0.93\pi=31.07\pi\ in^3$

assume

$\pi=3.1416$

$V=31.07(3.1416)=97.6\ in^3$

8 0

2 years ago

Which is a correct two column proof. Given <4 and

vladimir1956 [14]

The initial statement is: QS = SU (1)

QR = TU (2)

We have to probe that: RS = ST

Take the expression (1): QS = SU

We multiply both sides by R (QS)R = (SU)R

But (QS)R = S(QR) Then: S(QR) = (SU)R (3)

From the expression (2): QR = TU. Then, substituting it in to expression (3):

S(TU) = (SU)R (4)

But S(TU) = (ST)U and (SU)R = (RS)U

Then, the expression (4) can be re-written as:

(ST)U = (RS)U

Eliminating U from both sides you have: (ST) = (RS) The proof is done.

4 0

3 years ago

Ok need help please help Thank you

Step2247 [10]

96 1/2

there is ur answer i think :)

7 0

3 years ago