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pantera1 [17]
4 years ago
15

Ron and Harry both parked their cars at a parking lot. Ron parked his car for 8 hours at $3 per hour and Harry parked his car fo

r 7 hours at $3 per hour. They parked their cars for the same amount of time every day for 5 days. How much money Ron and Harry pay for parking altogether?
Mathematics
2 answers:
kotegsom [21]4 years ago
6 0
Ron parks his car at $24 per day (which is a heck of a lot of money) and Harry parks his car for $21 per day.
So...
21 x 5 = 105
24 x 5 = 120
So together they spent a small fortune ($225) on parking
Hope dis helps
SpyIntel [72]4 years ago
4 0
Alright, so Ron parked his car for 8 hours at $3 per hour.

Harry parked his car for 7 hours at $3 per hour.

So, per day Ron is spending (8 * 3) = $24 a day
and Harry is spending ( 7 * 3 ) = $21 a day

So now solve for 5 days. 24 * 5 = $120 21 * 5 = $105

Add both together
$120
+
$105

=
Your Answer:
$225 altogether.


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A container has peppermint gum and spearmint gum. There are 40 pieces of peppermint gum in the container and the ratio of pepper
Anit [1.1K]

Answer:

16 pieces of spearmint gum

Step-by-step explanation:

For every five pieces of peppermint gum, there are 2 pieces of spearmint gum.

First, divide the total number of peppermint gum by 5:

40/5 = 8

Multiply this number by 2 (pieces of spearmint) to get the number of spearmint gum pieces:

8 x 2 = 16

Proof:

Ratio is 40 : 16, dividing this by 8 will reduce the ratio to 5:2

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3 years ago
What changes occurred in the United States as a result of the cotton gin?
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3 years ago
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Solve Highschool Pre cal
Bezzdna [24]

Option C:

\ln 64 y^{2}

Solution:

Given expression: 2 ln 8 + 2 ln y

Applying log rule a \log b=\log b^{a}  in the above expression.  

⇒ 2 \ln 8+2 \ln y=\ln 8^{2}+\ln y^{2}

Applying log rule \log a+\log b=\log (a b) in the above expression.

⇒ \ln 8^{2}+\ln y^{2}=\ln \left(8^{2} y^{2}\right)

We know that 8^{2}=64

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Hence, the expression in single natural logarithm is \ln 64 y^{2}.

6 0
3 years ago
a fisherman travels 9mi downstream with the current in the same time he travels 3 mi upstream against the current. if the speed
netineya [11]

Answer:

10 mph

Step-by-step explanation:

speed of boat in still water = x

speed of current = 5

speed of boat with current (downstream) = x + 5

speed of boat against current (upstream) = x - 5

distance downstream = 9

distance upstream = 3

time = t

speed = distance/time

distance = speed × time

downstream:

9 = (x + 5)t

upstream:

3 = (x - 5)t

9 = xt + 5t

3 = xt - 5t

9 = xt + 5t

-3 = -xt + 5t

-----------------

6 = 10t

t = 0.6

9 = (x + 5)0.6

15 = x + 5

x = 10

5 0
2 years ago
<img src="https://tex.z-dn.net/?f=3x%20-%202y%20%3D%2043x%20%2B%202y%20%3D%208" id="TexFormula1" title="3x - 2y = 43x + 2y = 8"
den301095 [7]

3x - 2y = 8 +

===》 46x = 16

43x + 2y = 8

x = 16/46

x = 8/23

______________________________

3x - 2y = 8

3(8/23) - 2y = 8

24/23 - 2y = 8

2y = 24/23 - 8

y = 12/23 - 4

y = 12/23 - 92/23

y = - 80/23

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