Ask question

Ask question

All categories

4 years ago

7

The center is open for 11 hours each day. Each party takes three hours what is the maximum number of parties the Center can host

in a day

1 answer:

choli [55]4 years ago

3 0

It can host three party’s a day

You might be interested in

Over the course of a year, a company goes from 115 employees to 124 employees.

just olya [345]

An equation that could be used to find the percent change, p, in the number of employees is:

$\begin{array}{l}{p=\frac{\text {change in number of employees}}{\text {previous count}} \times 100} \\\\ {\mathrm{p}=\frac{9}{115} \times 100}\end{array}$

<h3><u>Solution:</u></h3>

Given that, Over the course of a year, a company goes from 115 employees to 124 employees.

Given that "p" represents the percent change

Percentage change equals the change in value divided by the absolute value of the original value, multiplied by 100.

$\text { Percent change "p" }=\frac{\text { change in number of employees }}{\text { previous count }} \times 100$

Change in number of employees = present count – previous count

So, change in number of employees = 124 – 115 = 9

$\begin{array}{l}{p=\frac{9}{115} \times 100} \\\\ {p=\frac{9}{23} \times 20} \\\\ {p=\frac{180}{23}=7.82}\end{array}$

The equation that is used to find the percent change is:

$\begin{array}{l}{\mathrm{p}=\frac{\text { change in number of employees }}{\text { previous count }} \times 100} \\\\ {\mathrm{p}=\frac{9}{115} \times 100}\end{array}$

7 0

3 years ago

This is my last question I need help with.

Viktor [21]

Answer:

Option 1

Step-by-step explanation:

The formula of constant porpotionality is

$y = kx$

or

$y = \frac{k}{x}$

where k is the constant of porpotionality.

This equation is direct variation so we will use

$y = kx$

The equation is in the form

$y = 1.5x$

1.5 is in k place so the constant of porpotionality is 1.5

3 0

3 years ago

Need your guyzes halp, no false answers and I will give you most of my points

Alex17521 [72]

Answer$32

Step-by-step explanation:

125 divided by 2 = 31.25 +00.05+32

8 0

2 years ago

Read 2 more answers

Determine which equations have the same solution set as – x + = 6x by recognizing properties, rather than solving. Check all tha

4vir4ik [10]

Answer:

1, 2, and 6

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

SOMEONE HELP ME IM FREAKING OUT I LITERALLY CANT WITH THIS QUESTION IM PRAYING PLEASE HELP ME IM SO SERIOUS IM GONNA END IT PLS

antiseptic1488 [7]

Answer:

$\sf -11+7\sqrt{2}$

Step-by-step explanation:

Given expression:

$\sf \dfrac{3-\sqrt{32}}{1+\sqrt{2} }$

Rewrite 32 as 16 · 2:

$\sf \implies \dfrac{3-\sqrt{16 \cdot 2}}{1+\sqrt{2} }$

Apply radical rule $\sf \sqrt{a \cdot b}=\sqrt{a}\sqrt{b}$

$\sf \implies \dfrac{3-\sqrt{16}\sqrt{2}}{1+\sqrt{2} }$

As $\sf \sqrt{16}=4$ :

$\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} }$

Multiply by the conjugate:

$\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} } \times \dfrac{1-\sqrt{2} }{1-\sqrt{2} }$

$\sf \implies \dfrac{(3-4\sqrt{2})(1-\sqrt{2})}{(1+\sqrt{2})(1-\sqrt{2})}$

$\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4\sqrt{2}\sqrt{2}}{1-\sqrt{2}+\sqrt{2}-\sqrt{2}\sqrt{2}}$

As $\sf \sqrt{2}\sqrt{2}=\sqrt{4}=2$ :

$\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4 \cdot 2}{1-\sqrt{2}+\sqrt{2}-2}$

$\sf \implies \dfrac{3-7\sqrt{2}+8}{1-2}$

$\sf \implies \dfrac{11-7\sqrt{2}}{-1}$

$\sf \implies -11+7\sqrt{2}$

7 0

2 years ago