Answer:
m<V = 11.2 degrees
Step-by-step explanation:
In ΔUVW, the measure of ∠W=90°, UV = 6.2 feet, and WU = 1.2 feet.
From the triangle;
UV = hypotenuse = 6.2feet
WU = opposite = 1.2feet
Required
m<V
Using the SOH CAH TOA identity
sin m<V = opp/hyp
sin m<V = WU/UV
sin m<V = 1.2/6.2
sin m<V = 0.1936
m<V = arcsin(0.1936)
m<V = 11.16
m<V = 11.2 degrees ((to the nearest tenth of a degree)
So first, we want to substitute in 15 to all the x variables.
So,
3x - 8y = 5
Becomes
3 * 15 - 8y = 5
Or,
45 - 8y = 5
So here, you can subtract 45 from both sides to move all like terms to one side.
-8y = 5 - 45
And then simplify:
-8y = -40
Then divide both sides by -8
y = 5
Answer:
(5,-3)
Step-by-step explanation:
Rewrite the equation in vertex form
y =-(x-5)^2 - 3
You take the value of -5 (that would be your x value) and change it to the opposite sign -> +5
Then you take -3 (that would be your y value) and take it as it is
therefore the answer is (5, -3)
I found the corresponding image. Pls. see attachment.
<span>The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is
2 (translation and rotation). A
rotation translation must be used to make the two polygons coincide.
A sequence of transformations of polygon ABCDE such that ABCDE does not coincide with polygon FGHIJ is
a translation 2 units down and a 90° counterclockwise rotation about point D </span>
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