The electrons needed by photosystem ii originate from water.
1) RNA polymerase finds the promoter sequence on DNA.
2)RNA polymerase reads the DNA and builds complementary sequence.
3) Intron séquences are spliced out and exons are joined together.
4) The ends of the mature transcript are protected before it leaves the nucleus.
5) The mRNA attachés to the ribosome.
6) transfer RNA arrives at the ribosome and the anticodon complements to the mRNA codon.
7)amino acids form peptide bonds as tRNA molecules match the mRNA.
After the cerebellum receives proprioceptive information from muscles carrying out a voluntary movement, where does it send corrective feedback to primary motor cortex and cerebral nuclei.
The cerebellum, also known as the corticocerebellum, has a close connection to the regulation of movement timing, rate, range, length, direction, and strength. The cerebellum receives information from the command neurons and also obtains feedback (afferent) from the proprioceptive terminals of the muscles, tendons and joints regarding what the actual movements produce .
All these information are combined and the correction signals are given to the motor cortex. The motor nuclei of the cranial nerves and spinal cord exert the lowest level of motor control. Through the closed feedback loop, this occurs.
Learn more about cerebellum here:
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Complete question:
Suppose "A" is a dominant gene for the ability to taste phenylthiocarbamide and "a" is a recessive gene for the inability to taste it. Which couples could possibly have both a child who tastes it and a child who does not?
a. father AA, mother aa
b. father Aa, mother AA
c. father Aa, mother Aa
d. father AA, mother AA
Answer:
c. father Aa, mother Aa
Explanation:
According to the given information, the ability to taste phenylthiocarbamide is a dominant trait and is imparted by the allele "A". This phenotype would be expressed in both homozygous and heterozygous conditions. The non-taster phenotype would be expressed in the homozygous recessive genotypes only.
To have both taster and non-taster children, both the parents should have at least one copy of the recessive allele. Among the given options, the father with genotype Aa and the mother with genotype Aa have the possibility to have both taster and non-taster children.
Aa x Aa= 3/4 taster (1/4 AA and 1/2 Aa): 1/4 non-taster (1/4 aa)
