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Tems11 [23]
3 years ago
14

A block of stone measures 15 cm X 15 cm X 20 cm. What is the total surface area of the stone?(Hint: A block has six sides.)

Mathematics
1 answer:
guajiro [1.7K]3 years ago
4 0
The answer would be 4500 cm ^3
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Write an equation to model growth or decay in the following scenario. A stock is declining at a rate of 25% of its value every 2
yawa3891 [41]

The exponential function that models this situation is:

y(t) = 225(0.75)^{\frac{t}{2}}

------------------------------------------

A decaying exponential function has the following format:

y(t) = y(0)(1 - r)^t

In which:

  • y(0) is the initial value.
  • r is the decay rate, as a decimal.

In this problem:

  • The stock started at $225, thus y(0) = 225.
  • Declines at a rate of 25% every 2 weeks, thus r = 0.25, t = \frac{t}{2}

The equation is:

y(t) = y(0)(1 - r)^t

y(t) = 225(1 - 0.25)^{\frac{t}{2}}

y(t) = 225(0.75)^{\frac{t}{2}}

A similar problem is given at brainly.com/question/24282972

3 0
2 years ago
Which descriptions are true of the function shown in the table? Check all that apply.
forsale [732]

Answer:

Linear

y=3.2x

Step-by-step explanation:

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6 0
3 years ago
Please answer!!! <br> ( 10 points)
andrezito [222]

Answer:

24

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
In the diagram below line l is parallel to line m which angles are congruent to angle 1 ​
Alchen [17]

ANSWER

\angle1   \cong \angle3

\angle1   \cong \angle8

\angle1   \cong \angle6

EXPLANATION

Since line l is parallel to line m,

\angle1   \cong \angle3

because the two angles are vertically opposite angles.

\angle1   \cong \angle8

because the two angles are corresponding angles.

\angle1   \cong \angle6

because the two angles are alternate exterior angles.

3 0
3 years ago
Now find the change in x. The change in x is . The average rate of change of f(x) = x2 + 5x −−12 from x = −2 to x = 1 is
Ahat [919]

Answer:

The average rate of change = 4.

Step-by-step explanation:

Here we have formula.

Average rate of change = f(b) - f(a)

                                           -----------

                                            b - a

Given: f(X) = x^2 + 5x - 12 interval [-2, 1]

Here a = -2 and b = 1

f(a) = f(-2) = (-2)^2 + 5(-2) -12

= 4 -10 -12

f(-2) = -18

f(b) = f(1) = (1)^2 + 5(1) - 12

= 1 + 5 -12

f(1) = 6 -12

f(1) = -6

Now apply these values in the above formula, we get

Average rate of change = [-6 - (-18)] / [1 -(-2)]

= [ -6 +18]/1 +2

= 12/3

= 4.

Therefore, the average rate of change = 4.

Hope this will helpful.

Thank you.

6 0
3 years ago
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