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2 years ago

Suppose the stock of the 3M company increases by $4 per share while all other Dow

Mathematics

1 answer:

lions [1.4K]2 years ago

7 0

Answer:

The Dow Jones Industrial Average increases.

Step-by-step explanation:

Since it is an average and one of the stocks increased, the Dow Jones Industrial Average will increase but not my much, since it is only one stock increasing and the amount it increased was only $4.

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C)PLEASE MAN PEOPLE ARE USING ME FOR POINTS

UNO [17]

The measures of spread include the range, quartiles and the interquartile range, variance and standard deviation. Let's consider each one by one.

Interquartile Range:

Given the Data -> First Quartile = 2, Third Quartile = 5

Interquartile Range = 5 - 2 = 3

Range: 8 - 1 = 7

Variance:

We start by determining the mean,

$\:1+\:2+\:3+\:3+\:3+\:5+\:8 / 7 = 3.57$

n = number of numbers in the set

Solving for the sum of squares is a long process, so I will skip over that portion and go right into solving for the variance.

$\sum _{i=1}^n\frac{\left(x_i-\bar{x}\right)^2}{n-1},\\\\=> SS/n - 1\\\\=> 31.714/7 - 1\\=> 5.28571$

5.3

Standard Deviation

We take the square root of the variance,

$\sqrt{5.28571} = 2.29906$

2.3

If you are not familiar with variance and standard deviation, just leave it.

3 0

3 years ago

Read 2 more answers

Learning Thoery In a learning theory project, the proportion P of correct responses after n trials can be modeled by p = 0.83/(1

elena-s [515]

Answer:

a) $P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

b) $P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

c) $0.75 =\frac{0.83}{1+e^{-0.2n}}$

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

d) If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

Step-by-step explanation:

For this case we have the following expression for the proportion of correct responses after n trials:

$P(n) = \frac{0.83}{1+e^{-0.2t}}$

Part a

For this case we just need to replace the value of n=3 in order to see what we got:

$P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

So the number of correct reponses after 3 trials is approximately 0.536.

Part b

For this case we just need to replace the value of n=7 in order to see what we got:

$P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

So the number of correct responses after 7 weeks is approximately 0.666.

Part c

For this case we want to solve the following equation:

$0.75 =\frac{0.83}{1+e^{-0.2n}}$

And we can rewrite this expression like this:

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

Now we can apply natural log on both sides and we got:

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

And we can see this on the plot attached.

Part d

If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

5 0

3 years ago

Needs solved now please!

kati45 [8]

Answer:

see explanation

Step-by-step explanation:

Given

(2m + 5n)² = (2m + 5n)(2m + 5n)

Each term in the second factor is multiplied by each term in the first factor, that is

2m(2m + 5n) + 5n(2m + 5n) ← distribute both parenthesis

= 4m² + 10mn + 10mn + 25n² ← collect like terms

= 4m² + 20mn + 25n² ← perfect square trinomial

6 0

2 years ago

Read 2 more answers

12p + 7 > 139 greater or less than

bazaltina [42]

Answer:

$\Huge \boxed{p>11}$

Step-by-step explanation:

First, subtract by 7 both sides of equation.

$\displaystyle 12p+7-7>139-7$

Solve.

$\displaystyle 139-7=132$

$12p>132$

Then, divide by 12 both sides of equation.

$\displaystyle \frac{12p}{12}=\frac{132}{12}$

Solve to find the answer.

$\displaystyle 132\div12=11$

$\huge \boxed{p>11}$ , which is our answer.

3 0

3 years ago

1. Write 1/5 as a decimal

bija089 [108]

Answer:

1.5

1.5%

10/0

7/20

35.1%

8.20%

8.20

Step-by-step explanation:

there u go

7 0

3 years ago