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nalin [4]
4 years ago
7

What is the solution set of the quadratic inequality 6x2+1<0

Mathematics
2 answers:
Free_Kalibri [48]4 years ago
3 0

Answer:

Solution set of the quadratic equation is, Empty set

Step-by-step explanation:

Given the quadratic equation: 6x^2+1>0  

Subtraction property of equality states that you subtract the same number to both sides of an equation.

Subtract both sides by 1 we get;

6x^2+1-1>0-1

Simplify:

6x^2>-1

Division property of equality states that you divide the same number to both sides of an equation.

Divide both sides by 6 we get;

\frac{6x^2}{6} >\frac{-1}{6}

Simplify:

x^2>\frac{-1}{6}

For any x in real number there does not exist any number x which satisfy

x^2>\frac{-1}{6} , therefore, there is no solution for this set of the quadratic inequality or in other word we can say that set of the solution is Empty set.

kirill [66]4 years ago
3 0
Minus 1 from both sides
6x^2<-1
divide both sides by 6
x^2<-1/6
take the square root of both sides
x<√(-1/6)
x<i√(1/6)

the solution is i√(1/6)
if you only consider real number, the solution set is empty
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Answer:

Step-by-step explanation:

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Consider a convex hexagon in which all pairs of opposite sides are parallel. Prove that if one pair of opposite sides have equal
hjlf

A pair of the opposite sides of a hexagon has equal length and this is proved below.

<h3>How to illustrate the hexagon?</h3>

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