Postulate (statement that is taken to be true) or theorem that can be used to prove that ABC=DCB is A. AAS
<h3>Explanation:
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The triangle is a polygon any 2-dimensional shape formed with straight lines) consist of the three edges and three vertices. It is one of the basic shapes in geometry. In triangle of ABC and triangle of DBC given the ∠A=∠D and ∠B=∠C
Then each of triangle that being 90° given in the diagram.
∠ABC=∠DCB
Then Δ ABC ≅ ΔD BC
When two triangles are congruent, then their areas are equal. Therefore, Area (ABC) = Area (DCB)
Therefore A. AAS postulate or theorem can be used to prove that ABC=DCB.
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The other example can be seen in the second attachment of picture. The question is still the same: Determine which postulate or theorem can be used to prove that ABC = DCB!
Then AC = DB
AB = DC
BC = BC, This side is equal to itself
Therefore the three sides of one triangle equal to 3 sides of the other. It means that the triangles are congruent. Therefore the answer is SSS
Hope it helps you to learn more about triangle.
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