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andrey2020 [161]
2 years ago
15

Find the slope of the line that passes through the two points given SW. * (4,3) & (3,-2)

Mathematics
1 answer:
nignag [31]2 years ago
4 0

Answer:

5

Step-by-step explanation:

The slope between (4,3) (3,-2) can be found using the following formula

m = (y2-y1)/(x2-x1)

   =(-2-3)/(3-4)

   = (-5)/(-1)

   =5

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use the rational root theorem to list all possible rational roots of the polynomial equation x^3-x^2-x-3=0. do not find the actu
Allisa [31]
None. <span>±</span>p/q, <span>where </span><span>p</span><span> is a </span>factor<span> of the </span>constant<span> and </span><span>q</span><span> is a </span>factor<span> of the leading </span>coefficient<span>.</span>
5 0
3 years ago
Read 2 more answers
Write the equation of a line that is parallel to y=0.6x + 3 and that passes through the point (-3,-5)
Mkey [24]

Answer:

\large\boxed{y=0.6x-3.2}

Step-by-step explanation:

The slope-intercept form:

y=mx+b

m - slope

b - y-intercept

We have

y=0.6x+3

Parallel lines have the same slope. Therefore we have the equation:

y=0.6x+b

The line passes through the point (-3, -5). Put the coordinates of the point to the equation and solve it for b:

-5=0.6(-3)+b

-5=-1.8+b            <em>add 1.8 to both sides</em>

-3.2=b

Finally we have:

y=0.6x-3.2

8 0
2 years ago
CAN SOMEONE PLEASE HELP ME????
Vitek1552 [10]

Answer:

Match it with x and y method

Step-by-step explanation:

3 0
3 years ago
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Hey! i’ll give brainliest please help
Iteru [2.4K]

Answer:

A subject and a predicate

Step-by-step explanation:

Have a good day :)

7 0
2 years ago
m∠AOB = 6x + 5, m∠BOC = 4x - 2, m∠AOC = 8x + 21
AnnZ [28]
The sum of angle AOB and angle BOC is equal tot he angle of AOC so

6x+5 +4x-2 = 8x+21

10x+3=8x+21

Subtract three and 8x from both sides

2x=18

Divide by two

x=9

Hope this helped!
6 0
3 years ago
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