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3 years ago

What is the equation, in point-slope form, for a line that goes through (8,- 4) and has a slope of -5/6

Mathematics

1 answer:

Norma-Jean [14]3 years ago

5 0

Answer:

$y + 4 = -\frac{5}{6}(x - 8)$

Step-by-step explanation:

In the Point-Slope Formula, $y - y_1 = m(x - x_1),$ all the negative symbols give the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL inserting the coordinates into the formula with their CORRECT SIGNS.

I am joyous to assist you anytime.

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Can someone help me?

12345 [234]

$A= ab \frac{sin \theta}{2}$
where A is area
a is side a lets say its 8cm
b is side b lets say its 7 cm
theta is 28

4 0

3 years ago

PLEASE HELP! THANKS!

Alina [70]

If you add everything up then
14x-2=180
14x=182
x= 13

So the angles would equal
2(13)+1= 27
3(13)-3= 36
9(13)= 117
The angles are 27 36 and 117
Which makes the smallest angle 27 which is B.

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3 years ago

Read 2 more answers

Determine whether this situation is linear or nonlinear? Explain your reasoning

jenyasd209 [6]

You didn't describe the situation so I can't answer.
However: if the graph of the situation is a straight line then the situation is linear, and if the graph is not a straight line then it is nonlinear.

8 0

3 years ago

Is anyone able to help me with this question:

Serga [27]

Answer:

not sure but this info might help you.

Step-by-step explanation:

the diagonal in the rectangle splits it into two right angled triangles, hence the hypotenuse is the diagonal.

once you find the measurement, we all know that a square has all sides equal and the diagonal splits it into 2 equilateral triangles. so, the side of the square =the diagonal's measurement.

7 0

3 years ago

Y=x^2-6x-16 in vertex form

satela [25.4K]

Answer:

$y=(x-3)^{2} -25$

Step-by-step explanation:

The standard form of a quadratic equation is $y=ax^{2} +bx+c$

The vertex form of a quadratic equation is $y=a(x-h)^{2} +k$

The vertex of a quadratic is (h,k) which is the maximum or minimum of a quadratic equation. To find the vertex of a quadratic, you can either graph the function and find the vertex, or you can find it algebraically.

To find the h-value of the vertex, you use the following equation:

$h=\frac{-b}{2a}$

In this case, our quadratic equation is $y=x^{2} -6x-16$ . Our a-value is 1, our b-value is -6, and our c-value is -16. We will only be using the a and b values. To find the h-value, we will plug in these values into the equation shown below.

$h=\frac{-b}{2a}$ ⇒ $h=\frac{-(-6)}{2(1)}=\frac{6}{2} =3$

Now, that we found our h-value, we need to find our k-value. To find the k-value, you plug in the h-value we found into the given quadratic equation which in this case is $y=x^{2} -6x-16$

$y=x^{2} -6x-16$ ⇒ $y=(3)^{2} -6(3)-16$ ⇒ $y=9-18-16$ ⇒ $y=-25$

This y-value that we just found is our k-value.

Next, we are going to set up our equation in vertex form. As a reminder, vertex form is: $y=a(x-h)^{2} +k$

a: 1

h: 3

k: -25

$y=(x-3)^{2} -25$

Hope this helps!

3 0

3 years ago