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4 years ago

2. Mr. Wheeler was ordering a part from Sears that he needed for his lawnmower. The price of

Mathematics

2 answers:

NeX [460]4 years ago

7 0

Answer:

49.95 x 7.25% =3.621375

49.95 + 3.62 = 53.37

Step-by-step explanation:

MAXImum [283]4 years ago

4 0

Answer:

53.68

Step-by-step explanation:

Write out the equation

x/49.95=7.25/100

Multiply 49.95 by 7.25

362.14

Divide by 100 for tax

3.73=tax

Add 49.95 and 3.73. Done!

53.68

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12x-4x+3+11 help me solve this problem

daser333 [38]

Answer:

8x + 14

Step-by-step explanation:

12x - 4x + 3 + 11 (Subtract 12x - 4x)

8x + 3 + 11 (Add 3 + 11)

8x + 14

Tip: the like-terms 12x and 4x can be subtracted like regular numbers because they have the same variable and exponent.

6 0

3 years ago

The solution to this system of equations lies between the x-values -2 and -1.5. At which x-value are the two equations approxima

katovenus [111]

D) -1.8
$-1.8$

6 0

3 years ago

Read 2 more answers

True or False? Using the quadratic formula allows you to find the x-intercepts of a quadratic equation.

levacccp [35]

True using the formula allows you to find the x intercepts of the equation

5 0

3 years ago

Z-(-3/4)= 6 1/2 I need help quick

liraira [26]

If Z is the unknown, then
Z-(-3/4)= 6 1/2
Z+3/4= 6 1/2
Z= 6 1/2 - 3/4
Z= 23/4 = 5 3/4

7 0

3 years ago

EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att

aliina [53]

$y=x(x-2)^2$
$\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0$
$\implies x=\dfrac23,x=2$

are the critical points, and judging by the picture alone, you must have $b=\dfrac23$ and $a=2$ . (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

$\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43$

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of $\dfrac{\mathrm dy}{\mathrm dx}=y'$ , which entails first finding the second derivative:

$y'=3x^2-8x+4$
$\implies y''=6x-8$

setting equal to 0 and finding the critical point:

$6x-8=0\implies x=\dfrac86=\dfrac43$

This is to say the minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ *occurs when $x=\dfrac43$ *, but this is not necessarily the same as saying that $\dfrac43$ is the actual minimum value.

The minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ is obtained by evaluating the derivative at this critical point:

$m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43$

4 0

4 years ago