How to solve your problem
Topics: Algebra, Quadratic Equation
2
+
1
=
−
3
2x+1=x-3
2x+1=x−3
Solve
1
Subtract
1
1
1
from both sides of the equation
2
+
1
=
−
3
2x+1=x-3
2x+1=x−3
2
+
1
−
1
=
−
3
−
1
2x+1{\color{#c92786}{-1}}=x-3{\color{#c92786}{-1}}
2x+1−1=x−3−1
2
Simplify
Subtract the numbers
Subtract the numbers
2
=
−
4
2x=x-4
2x=x−4
3
Subtract
x
x
from both sides of the equation
2
=
−
4
2x=x-4
2x=x−4
2
−
=
−
4
−
2x{\color{#c92786}{-x}}=x-4{\color{#c92786}{-x}}
2x−x=x−4−x
4
Simplify
Combine like terms
Multiply by 1
Combine like terms
=
−
4
x=-4
x=−4
Solution
=
−
4
Answer:
D) 4.7
Step-by-step explanation:
this perpendicular connection with the circle center cuts this intersecting line in half, which is therefore on both sides of x 6.5 long.
I assume 16 is the diameter, so the radius is 8.
therefore, x is one side of the right-angled triangle of
radius
x
half of the intersecting line
Pythagoras
8² = x² + (6.5)²
64 = x² + 42.25
21.75 = x²
x = 4.7
The value of the lesser integer is 28
