D. the upper quartile contains more values than the lower quartile.
Y = (2/3)x + 6
3y - 5x = 9
find an expression for y from the second equation:-
y = (5/3)x + 3
Now substitute this for y in the first equation:-
(5/3) x + 3 = (2/3)x + 6 Now solve for x:-
(5/3)x - (2/3)x = 6 - 3
x = 3
Now plug x = 3 into the second equation to find the value of y:_
3y - 5(3) =9
3y = 15+9 = 24
y = 8
So the solution is x = 3, y = 8
written as a set this is {3,8}.
Answer:
1. 8 meters
2.1dk
Step-by-step explanation:
Answer:
If the equation is in the form, ax + b = c, where x is the variable, you can solve the equation as before. First “undo” the addition and subtraction, and then “undo” the multiplication and division. Solve 3y + 2 = 11. Subtract 2 from both sides of the equation to get the term with the variable by itself.
Hope this helps :D
