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wariber [46]
2 years ago
13

What value of x makes this equation true? 12x - 15 = 6x - 3

Mathematics
1 answer:
djverab [1.8K]2 years ago
3 0

Answer:

2

Step-by-step explanation:

12 x - 15 = 6x - 3

12 x - 6x = 15 - 3

6x = 12

x = 12/6 = 2

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Answer:

4√2x.

Step-by-step explanation:

√32 = √2*√16 = 4√2.

√x^2 = x.

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Step-by-step explanation:

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Find the equation of this line<br><br> y = [?]x + [ ] <br> Please help
larisa [96]
<h2>Writing an Equation of a Line in Slope-Intercept Form</h2><h3>Answer:</h3>

y = [ -2 ] x + [ 1 ]\\

<h3>Step-by-step explanation:</h3>

<em>Please refer to my answer from this Question to know more about Slope-Intercept Form: <u>brainly.com/question/24599351</u></em>

We must first find the slope.

<em>Please refer to my Answer from this Questions to know more about Slopes of a Line:</em>

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We can see the marked points, (0,1) and (4, -7), are on the line.

Solving for the slope:

m = \frac{y_2 -y_1}{x_2 -x_1} \\ m = \frac{-7 -1}{4 -0} \\ m = \frac{-8}{4} \\ m = -2

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5 0
3 years ago
Ms. Lady works-out with Ms. Beetle; her average crawling time has increased to 4 feet per minute, while Ms. Beetle, who is used
ira [324]

Answer:

Senn needs to give Ms. Lady 4.6 minutes  head start

Senn needs to give Ms. Beetle 18.4 minutes  head start

The equation for each bug are;

For Senn, the equation for the experiment is 5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is 4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is 4 × (t₁ + 18.4) = 92 feet

Please find attached the required graph and table of values

Step-by-step explanation:

The given parameters are;

The average crawling time of Ms. Lady = 4 feet per minute

The average crawling time of Ms. Beetle = 2.5 feet per minute

The average crawling time of Senn = 5 feet per minute

The distance to the rose bush = 92 feet

Therefore, we have;

The time, t, duration for Senn to arrive at the Rose bush is given by the following relation,

Time, t = Distance, d/(Speed, s)

Given that the speed of the bugs is equal to their average crawling time, we have

For Senn

Time, t = 92/(5 ft/Min) = 18.4 minutes

For, Ms. Lady

Time, t = 92/(4 ft/Min) = 23 minutes

For, Ms. Beetle

t = 92/(2.5 ft/Min) = 36.8 minutes

Therefore;

Senn needs to give Ms. Lady 23 - 18.4 = 4.6 minutes head start

Similarly, Senn needs to give Ms. Beetle 36.8 - 18.4 = 18.4 minutes  head start

The equation for each bug are therefore;

For Senn, the equation for the experiment is given as follows ;

5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is given as follows;

4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is given as follows;

4 × (t₁ + 18.4) = 92 feet.

7 0
3 years ago
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