Answer:
Step-by-step explanation:
Find the Least Common Denominator (LCD) of \frac{1}{2},\frac{1}{3}
2
1
,
3
1
. In other words, find the Least Common Multiple (LCM) of 2,32,3.
LCD = 66
2 Make the denominators the same as the LCD.
\frac{1\times 3}{2\times 3}-\frac{1\times 2}{3\times 2}
2×3
1×3
−
3×2
1×2
3 Simplify. Denominators are now the same.
\frac{3}{6}-\frac{2}{6}
6
3
−
6
2
4 Join the denominators.
\frac{3-2}{6}
6
3−2
5 Simplify.
\frac{1}{6}
6
1
Answer:
14
Step-by-step explanation:
Substitute x = 2 into f(x)
f(2) = 7 × 2 = 14
Answer:
0.8888888888888
Step-by-step explanation:
J would equal -7.
I'm not exactly sure how I got that answer to be honest but I plugged -7 back in to make sure it was right.
-3(2*-7/3-6) = 32 is correct.
Answer:
c ≤ 330
Step-by-step explanation:
Given that:
Greatest weight = 23000 kg
Weight per crate = 60kg
Weight of other shipment already loaded = 3200kg
Total Number of 60kg crates, c that can be loaded
((Weight per crate * number of crates) + weight of other loaded shipment) ≤ greatest weight
((60 * c) + 3200 ≤ 23000
60c ≤ 23000 - 3200
60c ≤ 19800
c ≤ 19800 / 60
c ≤ 330