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Andre45 [30]
4 years ago
6

Samantha works at an animal shelter. She decides to track the total number of kittens that are brought in. The

Mathematics
1 answer:
Softa [21]4 years ago
8 0

Answer:

  C) The domain represents the weeks that have passed since Samantha started counting the kittens. The domain is all whole numbers.

Step-by-step explanation:

The problem statement tells you the independent variable w represents weeks that have passed. "Domain" refers to values the independent variable may have, so choices A or B make no sense here.

Time is measured continuously, and fractions of a week are possible. So, the domain could be <em>non-negative real numbers</em>. However, the answer choice D is "<em>all</em> real numbers", which includes negative numbers for which the function makes no sense.

The domain "all whole numbers" includes non-negative integers. It is reasonable to restrict the domain to non-negative integer numbers of weeks, so answer choice C is the best option.

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Which of the following statements are true?
Aneli [31]

Answer: It’s A

Step-by-step explanation:

4 0
3 years ago
An investor bought 700 shares of stock, some at $2.25 per share and some at $2.75 per share. If the total cost was $1825.00, how
statuscvo [17]

The shares of $2.25 are 200 and the shares of $2.75 are 700.

According to the question,

We have the following information:

An investor bought 700 shares of stock, some at $2.25 per share and some at $2.75 per share. And the total cost was $1825.00.

Now, let's take the shares of $2.25 to be x and the shares of $2.75 to be y.

So, we have the following expression:

x+y = 700

x = 700-y ....(1)

2.25x+2.75y = 1825 ...(2)

Putting the value of x from equation 1:

2.25(700-y)+2.75y = 1825

1575-2.25y+2.75y = 1825

1575+0.5y = 1825

0.5y = 250

y = 250/0.5

y = 500

Now, putting the value of y in equation 1:

x = 700-y

x = 700-500

x = 200

Hence, the shares of $2.25 are 200 and the shares of $2.75 are 700.

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7 0
1 year ago
Hi, can someone please give me a detailed explanation on how to solve this problem?
Dovator [93]

Answer:

Step-by-step explanation:

log3^(2x+3) = log243

(2x+3)log3 = log243

2x+3 = log243/log3

2x = (log243/log3)-3

x = [(log243/log3)-3]/2

x = (5-3)/2

x = 2/2

x = 1

Check:

3^2(1)+3 = 243

3^2+3 = 243

3^5 = 243

3×3×3×3×3 = 243

9×9×3 = 243

81×3 = 243

243 = 243

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3 years ago
When writing an standard number in scientific notation, the first factor must have a value ≥ 1 and &lt;
Oliga [24]
Thats true a number has to be greater than 1 and less than 10.
8 0
4 years ago
What is the first five nonzero multiples of 3 and 10
Masja [62]
Every multiples of 10s has a zero... you do know that... right?
5 0
3 years ago
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