Answer:
c. ![\frac{1}{12n} = {[12n]}^{-1}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B12n%7D%20%3D%20%7B%5B12n%5D%7D%5E%7B-1%7D)
Step-by-step explanation:
![[\frac{1}{4}][\frac{2}{5}][\frac{1}{2}][\frac{4}{7}][\frac{5}{8}][\frac{2}{3}][\frac{7}{n}] = \frac{560}{6720n} = [12n]^{-1} = \frac{1}{12n}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7B4%7D%5D%5B%5Cfrac%7B2%7D%7B5%7D%5D%5B%5Cfrac%7B1%7D%7B2%7D%5D%5B%5Cfrac%7B4%7D%7B7%7D%5D%5B%5Cfrac%7B5%7D%7B8%7D%5D%5B%5Cfrac%7B2%7D%7B3%7D%5D%5B%5Cfrac%7B7%7D%7Bn%7D%5D%20%3D%20%5Cfrac%7B560%7D%7B6720n%7D%20%3D%20%5B12n%5D%5E%7B-1%7D%20%3D%20%5Cfrac%7B1%7D%7B12n%7D)

* To make this simpler, reduce these two fractions in lowest terms.
I am joyous to assist you anytime.
23,307,609 that is the answer
Answer:
The sales level that has only a 3% chance of being exceeded next year is $3.67 million.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
In millions of dollars,

Determine the sales level that has only a 3% chance of being exceeded next year.
This is the 100 - 3 = 97th percentile, which is X when Z has a pvalue of 0.97. So X when Z = 1.88.




The sales level that has only a 3% chance of being exceeded next year is $3.67 million.
<span>If y varies directly with x, the formula of the equation is y=ax, where a is a constant.
y=ax
(21)=a(7)
a=3
y=ax
y=(3)(-1.66)
y=-4.98, x=-1.66
If y varies inversely with x, the formula of the equation is y=a/x, where a is a constant
y=a/x
9=a/2.5
a=22.5
y=22.5/x
y=22.5/-0.6
y=-37.5
I hope this helped! =)
I hope you didn't mind but I got this from a website called: answers.yahoo.com but I got your answer.
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