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3 years ago

How do you solve this problem? With explanation please!

Mathematics

2 answers:

jonny [76]3 years ago

5 0

Answer:

Step-by-step explanation:

divide 12 by 6

Sholpan [36]3 years ago

4 0

Answer:

D. divide 12 by 6

Step-by-step explanation:

to find x you need to get x alone

12=6x

divide 6 from both sides to cancel out the 6 on the right side

$\frac{12}{6} =\frac{6x}{6}$

6/6=1

2=x

hope this helps!

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Solve for x: 7+4x=13+x

Mnenie [13.5K]

$7+4x=13+x \\\\4x-x=13-7 \\\\3x=6 \\\\\boxed{x=\frac{6}{3}=2}$

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3 years ago

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What is 2 3/12 minus 1 8/12 equal to?

ArbitrLikvidat [17]

Answer:

7/12

Step-by-step explanation:

3/12=1/4

2 1/4=9/4

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1 2/3=5/3

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9/4-5/3=27/12-20/12=7/12

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3 years ago

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The area of a rectangle is 56 cm. The length is 2 cm more than x and the width is 5 cm less than twice x. Solve for x. Round to

mr Goodwill [35]

I hope this helps you

l=x+2

w=2x-5

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3 years ago

Solve for X. (1 point)<br> -ax + 3b > 5

Anarel [89]

Answer:

x<(3b-5)/a

Step-by-step explanation:

Subtract 3b from both sides: -ax>5-3b

Divide by -a, when dividing/multiplying a negative you flip the </> sign: x<(3b-5)/a

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3 years ago

Lim x--> 0 (e^x(sinx)(tax))/x^2

Tom [10]

Make use of the known limit,

$\displaystyle\lim_{x\to0}\frac{\sin x}x=1$

We have

$\displaystyle\lim_{x\to0}\frac{e^x\sin x\tan x}{x^2}=\left(\lim_{x\to0}\frac{e^x}{\cos x}\right)\left(\lim_{x\to0}\frac{\sin^2x}{x^2}\right)$

since $\tan x=\dfrac{\sin x}{\cos x}$ , and the limit of a product is the same as the product of limits.

$\dfrac{e^x}{\cos x}$ is continuous at $x=0$ , and $\dfrac{e^0}{\cos 0}=1$ . The remaining limit is also 1, since

$\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}=\left(\lim_{x\to0}\frac{\sin x}x\right)^2=1^2=1$

so the overall limit is 1.

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3 years ago