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1 year ago

Can somebody help find the surface area if this

Mathematics

2 answers:

GrogVix [38]1 year ago

3 0

The total surface area of the object shown in the diagram is 164 inches.

<h3>What is the total surface area?</h3>

The total surface area of a 3-dimensional object is the sum of the areas of the faces or surfaces of a 3-dimensional object. The object shown is the net of a cuboid.

Total surface area of a cuboid = 2 (lw + wh + lh)

where:

• l = length

• w = width

• h = height

2 { (10 x 3) + (10 x 4) + (4 x 3)}

2 (30 + 40 + 12)

2 x 82 = 164 inches

To learn more about cuboids, please check: brainly.com/question/9740924

#SPJ1

beks73 [17]1 year ago

3 0

The surface area of the figure is 164 square inches

<h3>How to determine the surface area?</h3>

From the net of the rectangular prism, we have the following dimensions:

Length = 4 inches

Width = 3 inches

Height = 10 inches

The surface area is calculated as:

Area = 2 * (Length * Width + Length * Height + Width * Height)

So, we have:

Area = 2 * (4 * 3 + 4 * 10 + 3 * 10)

Evaluate

Area = 164

Hence, the surface area of the figure is 164 square inches

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Given points A (1, 2/3), B (x, -4/5), and C (-1/2, 4) determine the value of x such that all three points are collinear

AlladinOne [14]

Answer:

$x=\frac{83}{50}$

Step-by-step explanation:

we know that

If the three points are collinear

then

$m_A_B=m_A_C$

we have

A (1, 2/3), B (x, -4/5), and C (-1/2, 4)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

step 1

Find the slope AB

we have

$A(1,\frac{2}{3}),B(x,-\frac{4}{5})$

substitute in the formula

$m_A_B=\frac{-\frac{4}{5}-\frac{2}{3}}{x-1}$

$m_A_B=\frac{\frac{-12-10}{15}}{x-1}$

$m_A_B=-\frac{22}{15(x-1)}$

step 2

Find the slope AC

we have

$A(1,\frac{2}{3}),C(-\frac{1}{2},4)$

substitute in the formula

$m_A_C=\frac{4-\frac{2}{3}}{-\frac{1}{2}-1}$

$m_A_C=\frac{\frac{10}{3}}{-\frac{3}{2}}$

$m_A_C=-\frac{20}{9}$

step 3

Equate the slopes

$m_A_B=m_A_C$

$-\frac{22}{15(x-1)}=-\frac{20}{9}$

solve for x

$15(x-1)20=22(9)$

$300x-300=198$

$300x=198+300$

$300x=498$

$x=\frac{498}{300}$

simplify

$x=\frac{83}{50}$

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Vitek1552 [10]

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Answer:

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