Answer:
A 2-column table with 3 rows. Column 1 is labeled x with entries 12, 15, 18. Column 2 is labeled y with entries 6, 9, 12.
Step-by-step explanation:
A 2-column table with 3 rows. Column 1 is labeled x with entries 12, 15, 18. Column 2 is labeled y with entries 6, 9, 12.
<span>8(-9-5x)
</span>=8(-9) - 8(5x)
= -72 - 40x
= - 40x - 72
expand by using distributive property
hope it helps
The cost of children’s ticket is $ 5
<h3><u>Solution:</u></h3>
Let "c" be the cost of one children ticket
Let "a" be the cost of one adult ticket
Given that adult ticket to a museum costs 3$ more than a children’s ticket
<em>Cost of one adult ticket = 3 + cost of one children ticket</em>
a = 3 + c ------ eqn 1
<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>
200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100

200a + 100c = 2100 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
Substitute eqn 1 in eqn 2
200(3 + c) + 100c = 2100
600 + 200c + 100c = 2100
600 + 300c = 2100
300c = 1500
<h3>c = 5</h3>
Thus the cost of children’s ticket is $ 5
The answer is 6. 15 triples with 9 and 12
2-3x=-x-8
-3x=-x-10
-2x=-10
X=5