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svetoff [14.1K]
3 years ago
11

Write the sum using summation notation, assuming the suggested pattern continues. 5 - 15 + 45 - 135 + ...

Mathematics
1 answer:
nalin [4]3 years ago
8 0

Answer:

<em>summation of five times negative three to the power of n from n equals zero to infinity</em>

Step-by-step explanation:

<u>Summation Notation </u>

It represents the sum of a finite or infinite number of terms. Let's analyze the terms of the given succession:

5-15+45-135+...

If we take 5 as a common factor, we have

5(1-3+9-27+...)

The parentheses contain the alternate sum/subtraction of powers of 3. The odd terms are positive, the even terms are negative, thus the exponent must be n starting from 0 or n-1 starting from 1

The summation is then represented by

\sum_{n=0}^{\infty}5(-3)^n

This corresponds with the option:

<u>summation of five times negative three to the power of n from n equals zero to infinity</u>

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An animal shelter estimates that it costs about $6 per day to care for each dog. If y represents the total cost of caring for a
TEA [102]

Answer:

A 2-column table with 3 rows. Column 1 is labeled x with entries 12, 15, 18. Column 2 is labeled y with entries 6, 9, 12.

Step-by-step explanation:

A 2-column table with 3 rows. Column 1 is labeled x with entries 12, 15, 18. Column 2 is labeled y with entries 6, 9, 12.

7 0
3 years ago
What is 8(-9-5x) simplified
VLD [36.1K]
<span>8(-9-5x) 
</span>=8(-9) - 8(5x)
= -72 - 40x
= - 40x - 72

expand by using distributive property

hope it helps
8 0
3 years ago
An adult ticket to a museum costs 3$ more than a children’s ticket. When 200 adult tickets and 100 children tickets are sold, th
antiseptic1488 [7]

The cost of children’s ticket is $ 5

<h3><u>Solution:</u></h3>

Let "c" be the cost of one children ticket

Let "a" be the cost of one adult ticket

Given that adult ticket to a museum costs 3$ more than a children’s ticket

<em>Cost of one adult ticket = 3 + cost of one children ticket</em>

a = 3 + c  ------ eqn 1

<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>

200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100

200 \times a + 100 \times c = 2100

200a + 100c = 2100 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>

Substitute eqn 1 in eqn 2

200(3 + c) + 100c = 2100

600 + 200c + 100c = 2100

600 + 300c = 2100

300c = 1500

<h3>c = 5</h3>

Thus the cost of children’s ticket is $ 5

6 0
3 years ago
Which number forms a Pythagorean triple with 8 and 10? Is it 6 or 15?
Firdavs [7]
The answer is 6. 15 triples with 9 and 12
5 0
3 years ago
Solve 2-3x = -x - 8
Vera_Pavlovna [14]
2-3x=-x-8
-3x=-x-10
-2x=-10
X=5
3 0
3 years ago
Read 2 more answers
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