is continuous over its domain, all real
.
Meanwhile,
is defined for real
.
If
, then we have
as the domain of
.
We know that if
and
are continuous functions, then so is the composite function
.
Both
and
are continuous on their domains (excluding the endpoints in the case of
), which means
is continuous over
.
Answer:
The required hypothesis to test is 
and 
.
Step-by-step explanation:
Consider the provided information.
It is given that the nightclub has recently surveyed a random sample of n = 250 customers of the club.
She would now like to determine whether or not the mean age of her customers is over 30.
Null hypotheses is represents as 
. Thus the null hypotheses is shown as:
The alternative hypotheses is represents as 
. Thus the alternative hypotheses is shown as:
Hence, the required hypothesis to test is and .
11,990
9% of 5500 is 495
(495+5500) [one year] x 2 [two years] = $11,990
At the end of 2 years, Aldo will owe $11,990.
Answers:
x = 2√2 units
y = 2√6 units
Explanation:
The given diagram is a right-angled triangle. This means that the special trig functions can be applied.
These functions are as follows:
sin θ = opposite / hypotenuse
cos θ = adjacent / hypotenuse
tan θ = opposite / adjacent
For getting x and y, we can choose to either work with θ = 30 or θ = 60.
I will work with 30.
1- For x:
We have:
θ = 30
x is the opposite side to θ
4√2 is the hypotenuse
Therefore, we can apply the sine function as follows:
sin θ = opposite / hypotenuse
sin (30) = x / 4√2
x = sin (30) * 4√2
x = 2√2 units
2- For y:
We have:
θ = 30
x is the adjacent side to θ
4√2 is the hypotenuse
Therefore, we can apply the cosine function as follows:
cos θ = adjacent / hypotenuse
cos (30) = y / 4√2
y = cos (30) * 4√2
y = 2√6 units
Hope this helps :)
Find the horizontal distance of 230 and find the Vertical distance , which is where the black dot is located.
The black dot is on 49 inches.
Now find the vertical distance f the black line at horizontal 230: This is on 47.5.
The difference between the two is : 49 - 47.5 = 1.5
The answer would be A. 1.5
