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Tamiku [17]
3 years ago
14

Find the sum of the interior angles of a pentagon show all work

Mathematics
1 answer:
tamaranim1 [39]3 years ago
4 0
The interior angles of a pentagon all add up to be 540°
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Find the first 4 terms in each sequence​
koban [17]

Answer:

a₁ = -21  (Given)

a₂ = -28

a₃ = -35

a₄ = -42

Step-by-step explanation:

First term a₁ = -21  (Given)

…………………………………

Second term a₂ :

a₂ = a_{2-1} - 7\\a_{1} - 7\\a_{1} = -21\\-21 - 7 = -28

…………………………………

Third term a₃ :

a₃ = a_{3-1} - 7\\a_{2} - 7\\a_{2} = -28\\-28 - 7 = -35

…………………………………

Fourth term a₄ :

a₄ = a_{4-1} - 7\\a_{3} - 7\\a_{3} = -35\\-35 - 7 = -42

5 0
2 years ago
Find the side length of the equilateral triangle whose area is the square root of 3 cm2
Alla [95]

Here, Given

Area of Equilateral triangle = 3cm2

therefore, we know;

Area of Equilateral triangle =( \sqrt{3}÷4)×a^{2}

so,

3 =( \sqrt{3}÷4)×a^{2}

3÷( \sqrt{3}÷4) = a^{2}

2.63 cm = a .

The area of ​​an equilateral triangle is the area covered by an equilateral triangle on a two-dimensional plane. An equilateral triangle is a triangle with all sides equal and all angles at 60 degrees. The area of ​​the shape is the number of unit squares that fit inside.

Here, "unit" refers to 1, and a unit square is a square with one side. Alternatively, the area of ​​an equilateral triangle is the total amount of space it surrounds in a two-dimensional plane.

Learn more about Area of  triangle  here: brainly.com/question/17335144

#SPJ4

6 0
2 years ago
Please help anybody it would help alot
antoniya [11.8K]
X=20

180-77=103

so then simplify (6x-17)=103
6x=120
x=20
5 0
3 years ago
How do i write 11 5/8 as an improper fraction
FinnZ [79.3K]
11 5/8 as a improper fraction 

1) Simplify Fraction 
⇒ Multiply denominator with whole number
8 x 11 = 88

⇒ Answer of multiplication and add the numerator 
88 + 5 = 93 

93/8 is improper Fraction. 


8 0
3 years ago
Read 2 more answers
What is the equation of the quadratic graph with a focus of (1 ,3) and a directrix of y=1?
zimovet [89]
Check the picture below.

now, we know the directrix is at y = 1, and the focus point is at 1,3, well, notice the picture, the distance between those fellows is just 2 units.

the vertex is half-way between those fellows, therefore, the vertex will be at 1,2.

the distance "p", from the vertex to either the directrix or focus, is really just 1 unit.  Since the focus point is above the directrix, is a vertical parabola, and it opens upwards, like in the picture, and since it opens up, the "p" value is positive, or +1.

\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
4p(x- h)=(y- k)^2
\\\\
\boxed{4p(y- k)=(x- h)^2}
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ( h, k)\\\\
 p=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
h=1\\
k=2\\
p=1
\end{cases}\implies 4(1)(y-2)=(x-1)^2\implies 4(y-2)=(x-1)^2
\\\\\\
y-2=\cfrac{1}{4}(x-1)^2\implies y=\cfrac{1}{4}(x-1)^2+2

4 0
3 years ago
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